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2 years ago

Geometry I need help find the value of theta and round your answer to the nearest tenth.

Mathematics

1 answer:

ira [324]2 years ago

3 0

Answer:

54deg

Step-by-step explanation:

We need to compute the inverse cosine of 10/17. I can't do it by hand, so I used a calculator and it arrived at ~53.97deg which is 54deg rounded to the nearest tenth.

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2. The actual tree on the left is 10 feet tall. The model tree on the right is 8 inches tall. What is the scale factor?

Lina20 [59]

Answer:

D. 1/15

Step-by-step explanation:

Actual tree = 10 ft = 12 × 10 = 120 in.

Model tree = 8 in.

Scale factor = model tree/actual tree

Scale factor = 8/120

Scale factor = 1/15

4 0

2 years ago

your classmate is starting a new fitness program. He is planning to ride his bicycle 45 minutes every day. He burns 10 calories

Verizon [17]

Burn you mean to cook like pele

3 0

3 years ago

What is the distance between (2,-9) and (-1,4)

kkurt [141]

Answer:

total distance might be 16

Step-by-step explanation:

|y2-y1/x2-x1|, plug it the numbers, if you got a negative number, its just positive since the equation is set to absolute value

7 0

2 years ago

PLEASE HELP ASAP!!!

Brut [27]

Answer:

The other angle would also measure 89°.

3 0

3 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago