we know the circumference shown for that picture is π miles, what would it be for the diameter? namely how long is the diameter of that circle whose circumference is π miles?
![\bf \textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\ \cline{1-1} C=\pi \end{cases}\implies \pi =\pi d\implies \cfrac{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=d\implies 1=d](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D%5Cpi%20d~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%20%5Ccline%7B1-1%7D%20C%3D%5Cpi%20%5Cend%7Bcases%7D%5Cimplies%20%5Cpi%20%3D%5Cpi%20d%5Cimplies%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%20%5Cpi%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B~~%5Cbegin%7Bmatrix%7D%20%5Cpi%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%3Dd%5Cimplies%201%3Dd)
Answer:
A. 1/2.
B. 15/26.
Step-by-step explanation:
Note when you have an 'OR' in the statement we <u>add </u>the probabilities.
A . Club or a diamond . There are 13 clubs and 13 diamonds so
The Required Probability = 13/52 + 13/52
= 1/4 + 1/4 = 1/2.
B. There are 4 jacks and 26 black cards.
The Required Probability = 4/52 + 26/52
= 1/13 + 1/2
= 2/26 + 13/26
= 15/26.
Answer:
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a)
h(t) , namely "h" variable is being represented in terms of "t".
h = dependent variable, depends on the value of "t", output.
t = independent variable, takes on values freely, input.
b)

c)

after 2 seconds, the ball is 11 meters high up.