Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is ![\frac{(AC-AD)+44-(AC-AD)+(AC+AD)+44-(AC+AD)}{4}=\frac{44+44}{4}=22](https://tex.z-dn.net/?f=%5Cfrac%7B%28AC-AD%29%2B44-%28AC-AD%29%2B%28AC%2BAD%29%2B44-%28AC%2BAD%29%7D%7B4%7D%3D%5Cfrac%7B44%2B44%7D%7B4%7D%3D22)
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
here's the answer
Step-by-step explanation:
hope this helps!
X = first class tickets , y = coach fare tickets
x + y = 42 <== equation about number of tickets sold
80x + 64y + 2880 <== equation about the revenue
Answer: 8f + 24
Explanation: You distribute the outside number to everything in the parentheses
Answer:
i think it has 4
Step-by-step explanation:
t + 15 is something on money