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kolbaska11 [484]
3 years ago
6

Help I dont get it and im stuck​

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:

20 km

Step-by-step explanation:

I used the Pothagarim Theorom.

  1. First, Multiply 12 by 12 to get 144
  2. Then, multiply 16 by 16 to get 256.
  3. Next, add 144 to 256 to get 400.
  4. Find the square root of 400 and get 20.
  5. 20 km would be your final answer

Hope this Helps!

<em>-kiniwih426</em>

<em>Btw, pls brainliest(if possible)</em>

ohaa [14]3 years ago
6 0

Answer:

B) 20

Step-by-step explanation:

Don't think to hard about the answer, all the numbers and text can be distracting.

Look at only the length of both Rachel 12 and Amos 16

Now use the Pythagorean theorem to find the unknown side in this right triangle.

a^{2} +b^{2} =c^{2} \\12^{2} +16^{2} =c^{2}

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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
ludmilkaskok [199]

Answer:

Option D, 192 m³

Step-by-step explanation:

Volume = base area × height

= (6×8/2)×8

= 192 m³

5 0
3 years ago
What additional information is needed to prove the triangles are congruent by SAS ?
DENIUS [597]

Answer:

Answer choice B was correct

Step-by-step explanation:

Line segment EB is congruent to line segment CB. I took the test.

4 0
2 years ago
T=an+b solve for b please help
Leni [432]
T=an+b
subtract an from each side
b=t-an
5 0
3 years ago
Read 2 more answers
Find the distance between the points (-1,-9) and (1,-4)
Snezhnost [94]

The distance between the two points is 5.4

Explanation:

The points are (-1,-9) and (1,-4)

The distance between the two points can be determined using the formula

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Substituting the values in the formula, we get,

d=\sqrt{(1+1)^{2}+(-4+9)^{2}}

Adding the values,

d=\sqrt{2^{2}+5^{2}}

Squaring the terms, we get,

d=\sqrt{4+25}

Simplifying, we have,

d=\sqrt{29}=5.4

Thus, the distance between the two points is 5.4

7 0
3 years ago
How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)&gt;0
scZoUnD [109]

Answer:

  x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

  x = -3 . . . sign change from + to -

  x = -1 . . . graph touches, but no sign change. - on either side of x=-1

  x = 4 . . . sign change from - to +

__

The function will be positive for x < -3 and for x > +4.

_____

<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

3 0
2 years ago
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