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3 years ago

How many triangles are formed by the angles and sides-unique triangle, no triangle, or many triangle

Mathematics

1 answer:

kirill115 [55]3 years ago

3 0

No triangle formed

Solution:

Given data:

One angle is 45°

Another angle is 108°

One side is 7 cm

To find how many triangles are formed for the given data.

Let the unknown side of a triangle be x°.

Sum of all the sides of a triangle = 180°

45° + 108° + x° = 180°

⇒ x° = 180° – 45° – 108°

⇒ x° = 27°

There is no such angle can be formed with 27° in the given image.

Hence there is no triangle can be formed.

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3 years ago

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1 year ago

-6.5+c=-4.12. How do you solve

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Answer: c=2.38

Step-by-step explanation:

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3 years ago

Jeffrey went to the movies with his friends. The tickets cost $8.50 each for students and they spent $15.00 altogether at the co

LenaWriter [7]

Answer:

4 people

Step-by-step explanation:

Let's first write an equation.

We want to find the number of tickets t

The total was $49 so our equation will equal $49 and they spent $15 in snacks so on the other side of the eqaution we have to add $15, on the same side as the snacks we need to add in the cost of tickets, which is $8.50 multiplies by t, or the total number of tickets.

$49 = $8.50t + $15

Solve for t, first subtract $15 from both sides.

$49 - $15 = $8.50t

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7 0

3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago