The quantity of sugar required for 2/4 of the recipe is 1/3 cups
<h3>How to solve fraction?</h3>
let
- x = quantity of sugar needed
Ratio of sugar to recipe
2/3 : 1 = x : 2/4
2/3 ÷ 1 = x ÷ 2/4
2/3 × 1/1 = x × 4/2
2/3 = x × 2
2/3 = 2x
x = 2/3 ÷ 2
x = 2/3 × 1/2
= 2/6
x = 1/3 cups
Therefore, the quantity of sugar required for 2/4 of the recipe is 1/3 cups
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Answer:
$618
Step-by-step explanation:
$1854 divided by 18 months = $103 per month
$103 x 12 months = $1236 paid in one year.
$1854originally owed - $1236 paid in a year = $618 still owed after one year of payments.
First you would have to isolate y.
3x - 3y = 18 -----> Subtract 3x from both sides
-3y = -3x + 18 --------> Now divide both sides by -3
y= x - 6
Now you replace the y with an f(x)
f(x) = x - 6
Answer:
24m+30
Step-by-step explanation:
6(4m+5)
Use the distributive property to multiply 6 by 4m+5.
24m+30
Let's solve your equation step-by-step.<span><span><span><span><span>− 14 </span>+ <span>6x </span></span>+ 7</span> −<span> 2x </span></span>=<span> 1 + <span>5x</span></span></span>
Step 1: Simplify both sides of the equation.<span><span><span><span><span>−14 </span>+ <span>6x </span></span>+ 7 </span>− <span>2x </span></span>=<span> 1 +<span> 5x</span></span></span><span>
Simplify: </span><span><span><span>4x - </span><span>7 </span></span>= <span><span>5x</span> + 1</span></span><span><span><span>4x</span> − 7</span>= <span><span>5x </span>+ 1</span></span>
Step 2: Subtract 5x from both sides.<span><span><span><span>4x</span> − 7</span> − <span>5x </span></span>= <span><span><span>5x </span>+ 1</span> −<span> 5x</span></span></span><span><span><span>− x </span>− 7 </span>=1 </span>
Step 3: Add 7 to both sides.<span><span><span><span>−x </span>− 7</span> + 7</span>=<span> 1+7</span></span><span><span>−x</span>=8</span>
Step 4: Divide both sides by -1.<span><span><span><span><span>−x/</span><span>−1 </span></span></span></span>=<span><span><span> 8/<span>−1</span></span></span></span></span><span>x=<span> −8</span></span>
Answer:<span>x= <span>−<span>8
hope this helps :)</span></span></span>
