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Gemiola [76]
3 years ago
15

Explain how you know if an ordered pair is a solution to an equation or not.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0
To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation. :)
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Step-by-step explanation:

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<em></em>

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Read 2 more answers
Determine whether each equation below does or does not represent a proportional relationship. support your answer using either a
Triss [41]

Answer:

  • As the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship.
  • As the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship.

Step-by-step explanation:

                                        <u><em>Solving equation A: y = x </em></u>

Let us consider the given equation A:

                                                      y = x

  • Putting x = 1 in y = x

y = x

y = 1    ∵ x = 1

Hence, (1, 1) is the ordered pair of  y = x

  • Putting x = 2 in y = x

y = x

y = 2    ∵ x = 2

Hence, (2, 2) is the ordered pair of  y = x

  • Putting x = 3 in y = x

y = x

y = 3    ∵ x = 3

Hence, (3, 3) is the ordered pair of  y = x

  • Putting x = 4 in y = x

y = x

y = 4    ∵ x = 4

Hence, (4, 4) is the ordered pair of  y = x

  • Putting x = 5 in y = x

y = x

y = 5    ∵ x = 5

Hence, (5, 5) is the ordered pair of y = x

Lets us consider all the ordered pairs i.e. (1, 1), (2, 2), (3, 3), (4, 4) and (5, 5) to make a table for y = x.

<em>y                 x</em>

1                  1

2                 2

3                 3

4                 4

5                 5

As from the table, lets take the ratio of every point i.e. y/x

  • For (1, 1), the ratio will be y/x ⇒ 1/1 = 1
  • For (2, 2), the ratio will be y/x ⇒ 2/2 = 1
  • For (3, 3), the ratio will be y/x ⇒ 3/3 = 1
  • For (4, 4), the ratio will be y/x ⇒ 4/4 = 1
  • For (5, 5), the ratio will be y/x ⇒ 5/5 = 1

Hence, the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship. Please also check the graph in attached<em> figure a.</em>

                                          <u><em>Solving equation A: y = x +2</em></u>

Let us consider the given equation A:

                                                         y = x + 2    

  • Putting x = 1 in y = x + 2

y = x + 2

y = 1 + 2 ⇒ 3  ∵ x = 1

Hence, (1, 3) is the ordered pair of y = x + 2

  • Putting x = 2 in y = x + 2

y = x + 2

y = 2 +2 ⇒ 4   ∵ x = 2

Hence, (2, 4) is the ordered pair of y = x + 2

  • Putting x = 3 in y = x + 2

y = x + 2

y = 3 + 2 ⇒ 5    ∵ x = 3

Hence, (3, 5) is the ordered pair of  y = x + 2

  • Putting x = 4 in y = x + 2  

y = x + 2  

y = 4 + 2 ⇒ 6   ∵ x = 4

Hence, (4, 6) is the ordered pair of  y = x + 2

  • Putting x = 5 in y = x + 2

y = x + 2

y = 5 +2 ⇒ 7    ∵ x = 5

Hence, (5, 7) is the ordered pair of y = x + 2

Lets us consider all the ordered pairs i.e. (1, 3), (2, 4), (3, 5), (4, 6) and (5, 7) to make a table for y = x + 2.

<em>y                 x + 2</em>

1                  3

2                 4

3                 5

4                 6

5                 7

As from the table, lets take the ratio of every point i.e. y/x

  • For (1, 3), the ratio will be y/x ⇒ 3/1 = 3
  • For (2, 4), the ratio will be y/x ⇒ 4/2 = 2
  • For (3, 5), the ratio will be y/x ⇒ 5/3 = 5/3
  • For (4, 6), the ratio will be y/x ⇒ 6/4 = 3/2
  • For (5, 7), the ratio will be y/x ⇒ 7/5 = 7/5

Hence, the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship. Please also check the graph in attached<em> figure a.</em>

<em>Keywords: equation, graph</em>

<em> Learn more equation and graphs from brainly.com/question/12767017</em>

<em> #learnwithBrainly</em>

6 0
3 years ago
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