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Gemiola [76]
3 years ago
15

Explain how you know if an ordered pair is a solution to an equation or not.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0
To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation. :)
You might be interested in
Is (0,0) a solution of the system y>x and x+y>0?
olga55 [171]
Plug the values (x,y)=(0,0) into the inequalities:

y\ \textgreater \ x \\
0\ \textgreater \ 0 \\
not \ true \\ \\
x+y\ \textgreater \ 0 \\
0+0\ \textgreater \ 0 \\
0\ \textgreater \ 0 \\
not \ true

0 isn't greater than 0, no (0,0) is not a solution to either of these inequalities.

The answer is D.
8 0
3 years ago
PLEASE HELP IM SO CONFUSED BY THIS
Yanka [14]
In a triangle, the three interior angles always add to 180°

m∠B = 180 - 30 - 80 = 70°

<span>D: 70</span>
4 0
3 years ago
What is the perimeter of triangle ABC? Round each step to the nearest tenth. Please help me
Ad libitum [116K]

I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².

Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.

Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.

Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.

Add each length up and you get a perimeter of roughly 11.4

8 0
3 years ago
are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of
galben [10]

Answer:

The best estimate of the area of the larger figure is 693\ cm^{2}

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

so

z=\frac{x}{y}

we have

x=12\ cm

y=9\ cm

substitute

z=\frac{12}{9}=\frac{4}{3} -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its  areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

so

z^{2}=\frac{x}{y}

we have

z=\frac{4}{3}

y=390\ cm^{2}

substitute and solve for x

(\frac{4}{3})^{2}=\frac{x}{390}

(\frac{16}{9})=\frac{x}{390}

x=390*16/9=693.33\ cm^{2}

4 0
3 years ago
8^1/3 or how to do it with any fractions
ahrayia [7]

Answer:

2

Step-by-step explanation:

When given a fractional power, you want to try to see if the base has any power that can be used to simplify the power.

Since a^b/c =

\sqrt[b]{ {a}^{c} }

8^1/3=

\sqrt[3]{ {8}^{1} }

8 times by it self it 8

cube root of 8 is three numbers that are the same and times by each other to give 8

2×2×2=8

》2

8 0
3 years ago
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