B^2 + 8b + 16 factoring polynomials with a leading coefficient

Mathematics

1 answer:

Tomtit [17]3 years ago

3 0

Answer:

(b +4)²

Step-by-step explanation:

Here, you recognize the constant as the square of half the coefficient of the linear term: 16 = (8/2)². This means the trinomial is a perfect square, so can be factored accordingly.

b² +8b +16 = (b +4)²

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