Can anyone please help ASAP, will give thanks and all that fun stuff

Mathematics

1 answer:

Sonja [21]4 years ago

5 0

We can begin by taking each part of the table and writing it out as a term of the geometric sequence. For example, for n=4, we have ar^3=6, and for n=9 we have ar^8=-192. Then, we can divide these two terms to get r^5=-32. Taking the fifth root on both sides, we get that r=-2. We can then just plug this in, getting -8a=6, or that a=-3/4, giving us B.

(every time i use a in this, i mean a1)

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How do I do this ? & how do I solve it for X&Y

soldier1979 [14.2K]

Simple....

you have:

4x+3y≤-12

To solve for X or Y just isolate the variable....

4x+3y≤-12
-3y -3y

4x≤-3y-12

Now divide by 4....

$\frac{4x}{4} \leq \frac{-3y-12}{4}$

$x \leq -\frac{3y}{4} -3$

Now for y:

4x+3y≤-12

4x+3y≤-12
-4x -4x

3y≤-4x-12

Divide by 3...

$\frac{3y}{3} \leq \frac{-4x-12}{3}$

$y \leq -\frac{4x}{3} -4$

This is the way to solve it.

Thus, your answer.

4 0

4 years ago

Suppose that a particular candidate for public office is in fact favored by 48%of all registered voters in the district. A polli

Mumz [18]

Answer: 0.1854

Step-by-step explanation:

Given : Suppose that a particular candidate for public office is in fact favored by 48% of all registered voters in the district.

Let $\hat{p}$ be the sample proportion of voters in the district favored a particular candidate for public office .

A polling organization will take a random sample of n=500 voters .

Then, the probability that p will be greater than 0.5, causing the polling organization to incorrectly predict the result of the upcoming election :

$P(\hat{p}>0.5)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.5-0.48}{\sqrt{\dfrac{0.48(0.52)}{500}}})\\\\=P(z>0.8951)\ \ [\because\ z=(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\=1-P(z\leq0.8951)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\ = 1-0.8146=0.1854$