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erik [133]
3 years ago
7

How can we write four between five?​

Mathematics
1 answer:
solmaris [256]3 years ago
8 0

Answer: You can write; 4 in between 5 as, Write 4 in Roman IV, in between F(IV)E.

Step-by-step explanation: is this what you want

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8. Divide: (6x² - 4x)+2x<br>A. 3x - 4x<br>B. 3x - 2x<br>C. 6x-2<br>D. 3x - 2​
kompoz [17]

Answer:

3x-2

Step-by-step explanation:

I think you meant (6x^2-4x) divided by 2x

if it isn't then pls comment what you meant

8 0
2 years ago
Four trucks were used to make deliveries. The drivers recorded the number of miles driven and the amount of gasoline used. Truck
deff fn [24]

Answer: Truck C

Step-by-step explanation: 14:1

8 0
3 years ago
Read 2 more answers
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
Does each relation reprsent a fuction? choose yes or no
mariarad [96]

Answer:

sorry for the questions i am not able to give answer

3 0
2 years ago
Adante begins to evaluate the expression 3 1/3 x 5 1/4 using the steps below
Liula [17]

Answer:

\frac{35}{2}

Step-by-step explanation:

To solve this problem we need to write the mixed fraction as a fractional number, as follows:

3 1/3 = 3 + \frac{1}{3} = \frac{9+1}{3} = \frac{10}{3}

5 1/4 = 5 + \frac{1}{4} = \frac{20+1}{4} = \frac{21}{4}

Then, evaluating the expression:

\frac{10}{3}×\frac{21}{4} = \frac{210}{12}

→ \frac{35}{2}

4 0
3 years ago
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