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3 years ago

I need help with this question

Mathematics

1 answer:

loris [4]3 years ago

4 0

The answer would be D. :) Hope this helps!

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Suppose you and some friends go to the movies and buy some snacks. The snack bar charges $2 for a box of candy and $6 for the “c

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If what you are trying to do is buy the most you can and still having some change left over then the answer would be 1 combo and 2 boxes of candy

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3 years ago

PLEASE HELP WILL MARK BRAINLIEST!!

Gre4nikov [31]

Answer:

Explanation below.

Step-by-step explanation:

1. a. $\sqrt{x} =12$

b. $\sqrt{x} ^{2}=12^{2}$

c. x=144

2. a. $\sqrt{x^{2} } =\sqrt{196}$

b. x= 14

$\sqrt{x} -4 +4= 8+4\\\sqrt{x} =12\\x= 3.46410161514 \\or \\2\sqrt{3}$

$2(x^{2} +3)=398\\x^{2} +3= 199\\x^{2} =196\\x=14$

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3 years ago

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Mississippi has the lowest median income at 40.6 thousand dollars. Mississippi also has about 207 bachelor’s degrees per 1,000 p

horsena [70]

Answer:

178

Step-by-step explanation:

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3 years ago

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Line p and line q are ______

tino4ka555 [31]

Line p and q are not parallel, because the two given alternate interior angles are not congruent. (It’s B)

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3 years ago

What is the recursive rule for the sequence 2, -1, 1/2 , -1/4

Helga [31]

Answer:

$a_n=\frac{-1}{2}a_{n-1}$

$a_1=2$

Step-by-step explanation:

The recursive rule is a term defined in terms of other terms in the sequence.

The is a geometric sequence because it has a common ratio.

The common ratio can be found by dividing a term by previous term.

For example, all of these are equal:

$\frac{-1}{2}$

$\frac{\frac{1}{2}}{-1}$

$\frac{\frac{-1}{4}}{\frac{1}{2}}$

They are all equal to $\frac{-1}{2}$ .

So we are saying:

$\frac{\text{term}}{\text{previous term}}}=\frac{-1}{2}$

More formally:

$\frac{a_n}{a_{n-1}}=\frac{-1}{2}$ .

Multiply both sides by $a_{n-1}$ :

$a_n=\frac{-1}{2}a_{n-1}$

When doing recursive form, you need to state a term of the sequence (or more depending on the recursive form you have).

So the first term is 2.

So the full thing for the answer is:

$a_n=\frac{-1}{2}a_{n-1}$

$a_1=2$

8 0

3 years ago