1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bezimeni [28]
3 years ago
5

I need help with this question

Mathematics
1 answer:
loris [4]3 years ago
4 0
The answer would be D. :) Hope this helps!
You might be interested in
Thirty-three students went out for junior high football. How many ways can the coach create a lineup of 11 players?
WITCHER [35]
Only 3 ways because 33 divided by 11 is 3.
7 0
4 years ago
Read 2 more answers
Can someone please help me figure out this problem. just figure out what 1,2, and 3
Aleksandr-060686 [28]
1 is 39. J don’t know about 2 and 3 though:(
4 0
3 years ago
Find the solution of y = 2x + 5 for x = 1
ArbitrLikvidat [17]

y = 2x+5

y = 2(1)+5

y = 2+5

y = 7

7 0
4 years ago
In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0
3 years ago
Mom can make 10 brownies from a 12-ounce package. How many ounces of brownie mix would be needed to make 50 brownies?
arsen [322]

Answer:

60 ounces

Step-by-step explanation:

İf she can make 10 brownies with 12 ounce mix then

For 50 she would need 5 × 12 = 60 ounces

3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the median?<br> –63–63–70–71–71–91–74–71
    5·1 answer
  • The sum of the squares of the digits of a positive two-digit number is 20, and the tens digit is 2 more than the units digit. fi
    8·1 answer
  • The data in the table represents the predicted price of a. Gallon of milk y,for numbers of years x. Which form of an equation wa
    11·2 answers
  • a car travels 83 7/10 miles on 2 1/4 gallons of fuel. which is the best estimate of the car travels on one gallon of fuel
    15·1 answer
  • The area of a triangular roof section with a base of 7 feet and a height of 3.5 is
    5·1 answer
  • Garden.
    7·2 answers
  • How many bacteria will there be in 10 hours if i started with one?
    13·2 answers
  • Solve the equation -(1-5x) = -8x + 25
    5·1 answer
  • II
    13·2 answers
  • on the following unit circle, \thetaθtheta is in radians. a unit circle with an angle from the positive x-axis to a ray labeled
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!