The line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
<h3>Parallel Equations</h3>
The given equation is:
y = 4x + 5
Compare y = 4x + 5 with the equation y = mx + c
m = 4, c = 5
The equation parallel to y = 4x + 5 will also have a slope, m = 4
The point-slope form of the equation of a line is given as:
y - y₁ = m(x - x₁)
substitute m = 4, x₁ = -2 and y = 1 into the equation above
y - 1 = 4(x - (-2)
y - 1 = 4(x + 2)
y - 1 = 4x + 8
y = 4x + 8 + 1
y = 4x + 9
Therefore the line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
Learn more on equation of a line here: brainly.com/question/13763238
Answer:
5,00000000
Step-by-step explanation:
6000000000
Answer:
x = -8
Step-by-step explanation:
y = 3x + 14
2x - 3y = -14
So, what is the substitution? Y of course, this is because y is equal to 3x + 14.
2x - 3 (3x + 14) = -14
Multiply 3 with the numbers in the parentheses.
2x - 9x + 42 = -14
So you maybe be wondering why it is a negative 7 instead of subtracting 9 with 2. Using PEMDAS, we always read from left to right. So it is basically 2 -9 and you get -7.
-7x + 42 = -14
Then subtract 42 from both sides.
-7x + 42 - 42 = -14 - 42
Simplify
-7x = -56
Divide 7 by both sides.
-7x / 7 = -56 / 7
x = -8
And you might ask, why we get x instead afterwards. This is because both -7 and 7 cancel each other out leaving us with x.
Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:
this is equivalent to:
thus, we can conclude that
x= 3.
Split the triangle into a 30-60-90 triangle. Since you have LM from that triangle, you can figure out the other sides. Then, using the leg from that triangle, the one next to it is a 45-45-90 triangle, meaning it's isosceles.
KM = 30 + 10√3
KL = 10√6
(sorry i'm not too sure if my "reasons" for statement/reason is correct)
