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Aleks04 [339]
3 years ago
5

Justin wants to use 188ft of fencing to,fence off the greatest possible retangular area for a garden .What dimensions should he

use? What will be the area of the garden?
Mathematics
1 answer:
marshall27 [118]3 years ago
4 0
The greatest area that can be enclosed by a given amount of material will always be a square...

M=2L+2W  so we can say:

2L=M-2W

L=(M-2W)/2

area is:

A=LW  and using L from above:

A=W(M-2W)/2

A=(MW-2W^2)/2

dA/dW=(M-4W)/2 

d2A/dW2=-4

Since acceleration, d2A/dW2, is a negative constant, when velocity, dA/dW=0, it is at an absolute maximum for A(W).

dA/dW=0 only when M-4W=0, 4W=M, W=M/4

from earlier we found L=(M-2W)/2 and using W from above we get:

L=(M-M/2)/2

L=(2M-M)/4

L=M/4

So L=W=M/4, thus it is a square.

That's the proof, anyway...

188=2x+2y

94=x+y

y=94-x

A=xy and using y from above:

A=94x-x^2

dA/dx=94-2x, d2A/dx2=-2, as explained earlier, since acceleration is a negative constant, when dA/dx=0, it is at an absolute maximum for A(x).

dA/dx=0 only when 94-2x=0, 2x=94, x=47

and from earlier, y=94-x, so y=94-47

y=47

So the dimensions that produce the greatest area are:

47ft by 47ft

And thus the greatest area is:

47^2=2209 ft^2
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3 years ago
In a study of the accuracy of fast food​ drive-through orders, one restaurant had orders that were not accurate among orders obs
Lesechka [4]

Complete Question

In a study of the accuracy of fast food drive-through orders, one restaurant had 32 orders that were not accurate among 367 orders observed. Use a 0.05 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable?

Answer:

The decision rule  is

  Fail to reject the null hypothesis

The conclusion is  

  There is sufficient evidence to show that the rate of inaccurate orders is equal to​ 10%

Step-by-step explanation:

Generally from the question we are told that

   The sample size is  n =  367

    The number of orders that were not accurate is  k = 32

    The population proportion for rate of inaccurate orders is  p = 0.10

The null hypothesis is  H_o :  p = 0.10

The alternative hypothesis is  H_a :  p \ne 0.10

Generally the sample proportion is mathematically represented as  

         \^ p = \frac{k}{n}

=>      \^ p = \frac{32}{367}

=>      \^ p = 0.0872

Generally the test statistics is mathematically represented as

         z= \frac{ \^ p - p }{ \sqrt{ \frac{ p(1 - p)}{ n} } }

=>      z= \frac{ 0.0872  - 0.10 }{ \sqrt{ \frac{ 0.10 (1 - 0.10 )}{367} } }  

=>      z= -0.8174

From the z table  the area under the normal curve to the left corresponding to  -0.8174 is  

         P(z <  -0.8173 )  = 0.20688

Generally the p-value is mathematically represented as

         p- value =  2 *  0.20688

=>      p- value =  0.4138

From the value obtained we see that  p-value >  \alpha hence

The decision rule  is

  Fail to reject the null hypothesis

The conclusion is  

  There is sufficient evidence to show that the rate of inaccurate orders is equal to​ 10%

 

4 0
2 years ago
Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals
LenaWriter [7]

Answer:

It will take 35.46 quarters for the account to grow to $3000.

Step-by-step explanation:

Since the annual rate is compounded quarterly, this can be calculated using the formula for calculating the future value as follows:

FV = PV * (1 + r)^n ............................ (1)

Where;

FV = future value or the amount the deposit expected to grow to = $3,000

PV = Present value or the amount place in the savings = $2,000

r = Quarterly rate = Annual rate / 4 = 4.6% / 4 = 0.046 / 4 = 0.0115

n = number of quarters it will take for the loan to grow to $3000 = ?

Substituting the values into equation (1) and solve for n, we have:

$3,000 = $2,000 * (1 + 0.0115)^n

$3,000 / $2,000 = (1.0115)^n

1.50 = (1.0115)^n

Loglinearise both sides, we have:

log(1.50) = n log(1.0115)

0.176091259055681 = n * 0.00496588710682352

n = 0.176091259055681 / 0.00496588710682352

n = 35.4601816891322

Rounding to the nearest hundredth, which also implies to rounding to 2 decimal places, we have:

n = 35.46

Since the the annual rate is compounded quarterly, it will therefore take 35.46 quarters for the account to grow to $3000.

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2 years ago
If justin has 90 tacos and loses 15 how many does he have
Ne4ueva [31]

Answer:75

Step-by-step explanation:

90-15=75

8 0
3 years ago
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pav-90 [236]

Answer:

The number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

Step-by-step explanation:

Here, the given function polynomial is :

P(x) : 5x^4 + 12x^3 – x^2 + 3x + 5 = 0

The Fundamental Theorem of Algebra says that a polynomial of degree n will have exactly n roots (counting multiplicity).

Now here, the degree if the polynomial is 4 (highest power of variable x).

So, according to the Fundamental Theorem, the given polynomial can have AT MOST 4 roots, counting Multiplicity.

Hence,  the number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

7 0
3 years ago
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