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eduard
3 years ago
14

When the fish-tank water has a pH of 8.0, the hydronium ion concentration is 1.0 × 10-8 mole per liter. What is the hydronium io

n concentration when the water has a pH of 7.0?
Chemistry
1 answer:
Illusion [34]3 years ago
6 0
You must know and use the formula for pH.


pH = - log [H3O+], where [H3O+] is the molar concentration of hydronium ion.


So, when pH is 8.0 => 8.0 = - log [H3O+] and you can use antilogarithm (the inverse function of logarithm) to find [H3O+], in this way:


[H3O+] = 10^-8 = 1 * 10 ^-8 M


When, pH = 7.0 =>

7.0 = - log [H3O+] => [H3O+] = 1 * 10^ -7 M


Answer: 1*10^-7 mole / liter
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Write the given numbers in standard notation, maintaining the same number of significant figures.
svetlana [45]

Answer:

0.0761.

0.0059.

Explanation:

Hello!

In this case, since the writing of numbers in standard notation given the scientific notation requires adding zeros to the left of the first nonzero digit, for the first number, we need to add two zeros as seven is the third digit position:

0.0761.

Next, we need to add three zeros as 5 would be the fourth digit:

0.0059.

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4 0
3 years ago
Which of the following suggests that a physical change has taken place in an ice cube
zaharov [31]
The melting of the ice cube indicates physical change has taken place
7 0
3 years ago
If you dilute 40.0 mL of a 7.0 M solution to make 100.0 mL of solution, what is the molarity of the dilute solution?
Burka [1]

Answer:

2.8M

Explanation:

The following data were obtained from the question:

Volume of stock solution (V1) = 40mL

Molarity of the stock solution (M1) = 7M

Volume of diluted solution (V2) = 100mL

Molarity of diluted solution (M2) =?

Using the dilution formula, we can easily find the molarity of the diluted solution as follow:

M1V1 = M2V2

7 x 40 = M2 x 100

Divide both side by 100

M2 = (7 x 40)/100

M2 = 2.8M

Therefore, the molarity of the diluted solution is 2.8M

3 0
3 years ago
Write a balanced half-reaction for the oxidation of chromium ion Cr + 3 to dichromate ion Cr 2 O − 2 7 in basic aqueous solution
SOVA2 [1]

Answer:

14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻

Explanation:

In order to balance a half-reaction we use the ion-electron method.

Step 1: Write the half-reaction

Cr³⁺(aq) = Cr₂O₇²⁻(aq)

Step 2: Perform the mass balance, adding H₂O(l) and OH⁻(aq) where appropriate

14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l)

Step 3: Perform the electric balance, adding electrons where appropriate

14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻

8 0
3 years ago
what mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? working on stoichiometry and
Yanka [14]
CI2 + 2Nal ---> 2NalCI + I2
Nal = 149.9 g/mol.
NaCI = 58.5 g/mol
2 mol Nal makes 2 mol NaCI
0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI
00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)
4 0
4 years ago
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