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3 years ago

What is the difference of 23x and 9x

Mathematics

2 answers:

Setler [38]3 years ago

6 0

14x if you you mean 23x - 9x then it's 14x but if you mean something else it's not 14x

Aleonysh [2.5K]3 years ago

5 0

Answer:

its 14x in plato

Step-by-step explanation:

23x - 9x = 14x ;)

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Is 8/10 equivalent to 4/5

nordsb [41]

Yes 8/10 is equivalent to 4/5 or 16/20 ...

6 0

3 years ago

Read 2 more answers

2) Plot these points on a piece of graph paper. Draw a line to connect each of the pairs indicated. Then, determine which line i

valina [46]

2) longest line is (-1, -3) and (-1, 7)

3) (-1, -3), (-6,2), and (2,4)

5 0

3 years ago

Can you please help me Step by step as well for brainliest

romanna [79]

Answer:

Step-by-step explanation:

42:7=ED:24

cross multiply 42 into 24.

Then divide by 7

you will get ED

Then use pythageorous theorem.

Ed square + 42 square=Ef square

Then do square root of Ef square

7 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Rectangle STUV has square PQRS removed, leaving an area of 92 m^2. Side PT is 4 m in length and side RV is 8m in length

Andrei [34K]

Answer:

117 $m^{2}$

Step-by-step explanation:

First think of the square that was removed. All 4 sides are equal but you don't know the length so lets gives them the variable X.

So to find the area of the rectangle, insert those variables into the area equation for a rectangle.

(RV + (X) ) (PT +(X)) = rectangle area

Now you are given what the area is if you remove the square. So subtract the the square's area from the equation above and set it equal to the size they told you.

(RV + (X)) (PT + (X)) - [(X)(X)] = 92 $m^{2}$

rectangle - square = remaining area

Now plug in the numbers you know and solve for X.

(8 + X) (4 + X) - ((X)(X)) = 92

Use FOIL to multiply the first part of the equation (first, outer, inner, last)

32 + 8x + 4x + $x^{2}$ - $x^{2}$ = 92

32 + 12x = 92

12x = 60

x = 5

So now you know the size of the square. Each side is 5m. So add 5m onto the top of the rectangle and onto the side. The top is 13m and the side is 9m. The area of the rectangle is the length times the height to 13 x 9 which is 117 $m^{2}$

6 0

2 years ago