You have to answer other people’s questions.
Answer:
Distribute - will put all of the layers in a straight line across the image
Answer:
Giving that: The following is a sequence of undo-log records written by 2 transactions T and U:
< START T >;
< T,A,10 >;
< START U >;
< U, B, 20 >;
< T, C, 30 >;
< U, D, 40 >;
< Commit U >;
< T, E, 50 >;
< Commit T >;
1. < START U >
Recovery action in this case will be undo(-1) and undo(0). All restored to its original Value
log records < T, A, 10 >, < T, abort >; as written out
2. < T, E, 50 >
Recovery action in this case will be undo(8) and redo(0). A and C is restored to its original value, B and D are set to 20 and 40
log records <T, C, 30 >, < T, A, 10 >, < T, abort > are written out
3. < Commit T >
Recovery action in this case will be redo(7) and redo(4). A and C are set to 10 and 30, B and D are set to 20 and 40
The following cose will be used to copy assignment operator for CarCounter
<u>Explanation:</u>
Complete Program:
#include <iostream>
using namespace std;
class CarCounter
{
public:
CarCounter();
CarCounter& operator=(const CarCounter& objToCopy);
void SetCarCount(const int setVal)
{
carCount = setVal;
}
int GetCarCount() const
{
return carCount;
}
private:
int carCount;
};
CarCounter::CarCounter()
{
carCount = 0;
return;
}
// FIXME write copy assignment operator
/* Your solution goes here */
CarCounter& CarCounter::operator=(const CarCounter& objToCopy)
{
if(this != &objToCopy)
carCount = objToCopy.carCount;
return *this;
}
int main()
{
CarCounter frontParkingLot;
CarCounter backParkingLot;
frontParkingLot.SetCarCount(12);
backParkingLot = frontParkingLot;
cout << "Cars counted: " << backParkingLot.GetCarCount();
cout << endl << endl;
system("pause");
return 0;
}
