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sweet-ann [11.9K]
4 years ago
10

Consider the following data: 3,4,6,7,9,9,11

Mathematics
1 answer:
kodGreya [7K]4 years ago
3 0
The data is already sorted for us. The median of this set is the middle most value which is 7 (in slot 4; three values to the left and three values to the right). 

So the median is originally 7

If we add 5 to each data value we get
3+5 = 8
4+5 = 9
6+5 = 11
7+5 = 12
9+5 = 14
9+5 = 14
11+5 = 16

So the old data set
{3,4,6,7,9,9,11}
shifts to
{8,9,11,12,14,14,16}
after we add 5 to each value

The middle most value of the updated set is 12. It corresponds exactly to the old median of 7.

So we technically didn't even need to add 5 to all of the values to see what the new median would be. We simply need to add 5 to the old median to get the new median

I.e,
(new median) = (old median) + 5

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In right triangle RQS, ∠Q is a right angle, RQ=55, QS=48, and RS=73.
kari74 [83]

The ratio of cos S in triangle RQS is 48 / 73

<h3 /><h3>Right angle triangle:</h3>
  • It has one angle as 90 degree
  • The sides can be found using Pythagoras theorem

∠Q = 90 degrees

Therefore, Finding cos S,

opposite side = RQ = 55

Hypotenuse = RS = 73

Adjacent side = QS = 48

Therefore,

cos S = adjacent / hypotenuse

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learn more on right angle triangle: brainly.com/question/13907707?referrer=searchResults

5 0
2 years ago
I need help completing the missing value
elixir [45]

Answer:

x= -8

Step-by-step explanation:

Since you know y=8 you plug it into the equation

-4x -8=24

you then add 8 to each side

-4x=32

then divide by -4

x=-8

5 0
3 years ago
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Give me a example of fractions
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A study conducted at a certain college shows that 6868​% of the​ school's graduates find a job in their chosen field within a ye
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Answer: Hello mate!

each school graduate has a 68% to find a job in their chosen field within a year after graduation.

And we want to know the probability for a randomly chosen group of 11 graduates to all get a job in their area within a year of graduating.

(you used the numbers 6868% and 1111, I am assuming that you write this wrong and repeated the numbers)

Ok! so each of the 11 students has the same probability of 0.68 to find the job. Then the joint probability for the 11 events ( where the events is that each one finds a job) is the product of the probability for each one.

P = (0.68)^11 = 0.01437

and if we round it to the nearest thousandth we get:

p = 0.014

3 0
3 years ago
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