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Levart [38]
3 years ago
8

Find a 2 × 2 matrix b ≠ o and b ≠ i2 such that ab = ba, where a = 1 7 0 1 . b =

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0
If \mathbf A is invertible, then we can simply choose \mathbf B=\mathbf A^{-1} because for any invertible matrix \mathbf X by definition we must have \mathbf{XX}^{-1}=\mathbf X^{-1}\mathbf X=\mathbf I.

We have \det\mathbf A\neq0, as

\det\mathbf A=\begin{vmatrix}1&7\\0&1\end{vmatrix}=1\times1-0\times7=1

which means \mathbf A is non-singular and has an inverse. The inverse itself would be

\mathbf A^{-1}=\dfrac1{\det\mathbf A}\begin{bmatrix}1&0\\-7&1\end{bmatrix}^\top=\begin{bmatrix}1&-7\\0&1\end{bmatrix}
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Answer:

\implies\boxed{ 10^a = 300 }

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We are provided logarithmic equation , which is ,

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  • Here we took the base as 10 , since nothing is mentioned about that in Question .

Say if we have a expoteintial equation ,

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<u>In</u><u> </u><u>logari</u><u>thmic</u><u> </u><u>form</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>,</u><u> </u>

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