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Levart [38]
3 years ago
8

Find a 2 × 2 matrix b ≠ o and b ≠ i2 such that ab = ba, where a = 1 7 0 1 . b =

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0
If \mathbf A is invertible, then we can simply choose \mathbf B=\mathbf A^{-1} because for any invertible matrix \mathbf X by definition we must have \mathbf{XX}^{-1}=\mathbf X^{-1}\mathbf X=\mathbf I.

We have \det\mathbf A\neq0, as

\det\mathbf A=\begin{vmatrix}1&7\\0&1\end{vmatrix}=1\times1-0\times7=1

which means \mathbf A is non-singular and has an inverse. The inverse itself would be

\mathbf A^{-1}=\dfrac1{\det\mathbf A}\begin{bmatrix}1&0\\-7&1\end{bmatrix}^\top=\begin{bmatrix}1&-7\\0&1\end{bmatrix}
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Nikolay [14]
The original number is 7 i think.
10(x^2) = 70x
10x^2 - 70x = 0
x^2 -7x =0
Δ= b^2 -4ac
where c doesnt exist=0
Δ= 49
-b ± √Δ /2a
7 ± √49 /2
7±7/2
x is either 14/2= 7
or 1/2, which doesnt work.

Lets see:
10(7^2) = 70•7
10•49 = 490
and that is right.

i hope my logic is correct.
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3 years ago
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Step-by-step explanation:

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