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monitta
2 years ago
13

11-1/2y=3+6x solve for y

Mathematics
1 answer:
BartSMP [9]2 years ago
3 0
Y=-12x+16 

Hope it's what you wanted ^.^ 
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How can you determine the domain and range of function.
Mice21 [21]

Answer:

The domain of a function is the complete set of possible values of the independent variable.

In plain English, this definition means:

The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

When finding the domain, remember:

The denominator (bottom) of a fraction cannot be zero

The number under a square root sign must be positive in this section

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Help don’t comment if u ain’t gon help please
Naya [18.7K]
If you want a quicker answer on that, use photo math. If you take pictures of all of those individually, youll get your answer. Apologize for not giving an answer to your problem but i figured id let you know because its faster then coming on here and asking.
6 0
2 years ago
a 4 sided cube, numbered 1-4, is rolled twice. Determine the sample space. how many possible outcomes are there?
kherson [118]

Answer:

16

Step-by-step explanation:

1        1

1        2

1        3

1        4

2        1

2        2

2        3  

2        4

Three and four are done exactly the same way. the total is 16 ways.  

3 0
3 years ago
April and Cody invest $5,000 each at their local bank. April invests at a 4% simple interest rate, and Cody invests at a 4% inte
maria [59]

Answer:

  • $24.32

Step-by-step explanation:

<u>The difference in balances is:</u>

  • 5000*(1 + 0.04)^3 - 5000*(1 + 0.04*3) =
  • 5624.32 - 5600 =
  • 24.32
3 0
3 years ago
If two polygons are SIMILAR, then the corresponding sides must be and the corresponding angles must be .
AveGali [126]

Answer:

Their sides must be in the same ratio and their angles must be equal.

Step-by-step explanation:

If two polygons are similar their sides must be in the same ratio and their angles must be equal.

e. g. -

If ABCDEF  and GHIJKL be the two polygons,

then,

\frac{AB}{GH} = \frac{BC}{HI} = \frac{CD}{IJ} = \frac {DE}{JK} = \frac {EF}{KL} = \frac{FA}{LG}

and,

∠ABC = ∠GHI ; ∠BCD =∠HIJ ; ∠CDE = ∠IJK ; ∠DEF =∠JKL ; ∠EFA =∠KLG;

∠FAB = ∠LGH .

5 0
3 years ago
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