. Correct option C)5.38
<u>Step-by-step explanation:</u>
Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth. picture is attached . Let's find out:
In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

By Pythagoras Theorem ,

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore ,
. Correct option C)5.38
Answer:
see below
Step-by-step explanation:
Vertical angles are formed by two lines and are opposite each other
Vertical angles are equal
Answer:

Step-by-step explanation:
