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3 years ago

What is the measure of Arc E B C?

Mathematics

1 answer:

Leona [35]3 years ago

6 0

<h2>Answer:</h2>

<h3>The measure of arc (EBC) is 220°.</h3>

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To determine drug dosages, doctors estimate a person’s body surface area (BSA) (in meters squared) using the formula BSA = √ h m

krok68 [10]

Answer:

Step-by-step explanation:

Given that a person’s body surface area (BSA) (in meters squared) using the formula

$BSA =\frac{\sqrt{hm} }{60}$

We are to calculate the rate of change of BSA with respect to mass for a person of constant height h = 180 from m =70 to m =80

For this we calculate BSA for 80 kg and BSA for 70 kg first

Rate of change = $BSA(80)-BSA(70)$

= $\frac{\sqrt{180*80} }{60} -\frac{\sqrt{180*70} }{60} \\=2-1.871\\=0.129$

i.e. rate of change per 10 kg is 0.129

No BSA does not increase more rapidly

7 0

3 years ago

denis23 [38]

Answer:

$B = 325$

Step-by-step explanation:

Given

Total = 900

Singing = 600

Dancing = 500

None = 125

Required

Determine the number of students that participate in both

Representing; Singing with S, Dancing with D, Both singing and dancing with B and None with N;

In Set Notation;

$Total = (S - B) + (D - B) + N + B$

Substitute 900 for Total, 600 for S, 500 for D and 125 for N

$900 = (600 - B) + (500 - B) + 125$

Open Brackets

$900 = 600 - B + 500 - B + 125 + B$

Collect Like Terms

$900 = 600 + 500 + 125 - B - B + B$

$900 = 1225- B - B + B$

$900 = 1225- B$

Collect Like Terms

$900 - 1225 = -B$

$-325 = -B$

Multiply both sides by -1

$-1 * -325 = -B * -1$

$325 = B$

Reorder

$B = 325$

<em>Hence, the number of students that do not participate in both is 325</em>

4 0

3 years ago

Use the quadratic formula to solve 2x^2 + 2x - 12?

Firdavs [7]

Answer:

Step-by-step explanation:

(x+2)(x-3)

8 0

3 years ago

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A video game developer

vitfil [10]

Answer:

y = 13x

Step-by-step explanation:

If "y" represents how much he earns total

and "x" represents the number of games sold

then the equation is $y=65\frac{x}{5}$

which can be simplified to $y = 13x$

8 0

3 years ago

A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t

Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

$\frac{99}{100}\times 1000$

$=0.99\times 1000$

$= 990$ kg

Now, at the end of the trip it is 98% of weight. So, let $x$ kg of water has been evaporated. So, remaining weight of the watermelon is $1000-x$ .

If $x$ kg of water is removed, then the amount of water left is $990-x$ .

As per question, water now weighs 98% of the total weight. So,

98% of ( $1000-x$ ) = $990-x$

$\frac{98}{100}\times (1000-x)=990-x$

$980-0.98x=990-x$

$-0.98x+x=990-980$ (Bringing like terms on one side)

$0.02x=10\\x=\frac{10}{0.02}=500\ kg$

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = $1000 - x$ = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

7 0

3 years ago

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