Car m left town q and car n left town p at the same time. at noon car m traveled 2/3 of the distannce from q to p and car n had traveled 3/4 of the distance from p to q. what fraction of the distance between the two towns is the distance between the two cars at noon?
1 answer:
Answer:
Suppose the distance from q to p is 12 metres.
then, distance travelled b y car m 2/3 will be:
12 * ⅔
= 24 / 3
= 8 metres
and distance travelled by car n 3/4 will be:
12 * ¾
= 36 / 4
= 9 metres
under these conditions, the fraction of distance b/w them will be:
9 - 8
= 1 metres
And under general conditions, (same as above)
¾ - ⅔
by taking L.C.M
= 9-8/12
= 1/12 fraction
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Answer:
See below.
Step-by-step explanation:
Sin (4π/3) = -sqrt(3)/2
Cos(4π/3) = -1/2
The answer is 1.5 bc 0.75 times 2 since it’s the midpoint
1= 5/4
2= -103/40
1st explanation
-12/15 + 4/5 + 7/12
-8 + 48 + 35/60
75/60
5/4
2nd explanation
-1 3/5 + 5 1/8 - 6 1/10
-8/5 + 41/8 + 61/10
- 64 + 205 + 244 / 40
-103/140
-103 / 40
Answer:
False
Explanation:
5 is 1/5 of 25
2 is 1/10 of 20
Answer: A centroid of a triangle is the point where the three medians of the triangle meet that is what i got on my test hope this helps :)
