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vlada-n [284]
2 years ago
9

Car m left town q and car n left town p at the same time. at noon car m traveled 2/3 of the distannce from q to p and car n had

traveled 3/4 of the distance from p to q. what fraction of the distance between the two towns is the distance between the two cars at noon?
PLEASE ANSWER ASAP!!
BRAINLIEST
Mathematics
1 answer:
seropon [69]2 years ago
6 0

Answer:

Suppose the distance from q to p is 12 metres.

then, distance travelled b y car m 2/3 will be:

                                              12 * ⅔

                                            = 24 / 3

                                            = 8 metres

and distance travelled by car n 3/4 will be:

                                              12 * ¾

                                            = 36 / 4

                                            = 9 metres

under these conditions, the fraction of distance b/w them will be:

                                            9 - 8

                                          = 1 metres

And under general conditions, (same as above)

                                       ¾ - ⅔  

             by taking L.C.M

                                    =  9-8/12

                                    = 1/12 fraction

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Step-by-step explanation:

It is convenient to write the equations in standard form.

Multiplying the first equation by 21 gives ...

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Then the system of equations in standard form is ...

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Subtracting the first from the second, we get ...

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The solution is (x, y) = (77/240, -3/10).

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