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vlada-n [284]
2 years ago
9

Car m left town q and car n left town p at the same time. at noon car m traveled 2/3 of the distannce from q to p and car n had

traveled 3/4 of the distance from p to q. what fraction of the distance between the two towns is the distance between the two cars at noon?
PLEASE ANSWER ASAP!!
BRAINLIEST
Mathematics
1 answer:
seropon [69]2 years ago
6 0

Answer:

Suppose the distance from q to p is 12 metres.

then, distance travelled b y car m 2/3 will be:

                                              12 * ⅔

                                            = 24 / 3

                                            = 8 metres

and distance travelled by car n 3/4 will be:

                                              12 * ¾

                                            = 36 / 4

                                            = 9 metres

under these conditions, the fraction of distance b/w them will be:

                                            9 - 8

                                          = 1 metres

And under general conditions, (same as above)

                                       ¾ - ⅔  

             by taking L.C.M

                                    =  9-8/12

                                    = 1/12 fraction

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Further explanation:

We have to determine first of all if the sequence is arithmetic or geometric.

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Given sequence is:

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The common difference is 10 which is same for all consecutive terms. So the sequence is an arithmetic sequence.

The general formula for arithmetic sequence is:

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Putting the values of a1 and d

a_n= 12+(n-1)(10)\\a_n=12+10n-10\\a_n=2+10n

The explicit rule for given sequence is:

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Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/1522572
  • brainly.com/question/2491745

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