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Hoochie [10]
2 years ago
14

Which statement best describes the area of the triangle shown below?

Mathematics
1 answer:
wel2 years ago
7 0

Answer:

It is twice the area of a rectangle of length 4 units and width 2 units.

Step-by-step explanation:

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The area of the smaller rectangle is 320*3/8=120 ft2
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Upper bound and lower bound of 17
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Hey there this si the upper and lower bound for 17

16.5<17<17.5

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The cost of making a large circle is 1.50. The cost of making the smaller circle is 3/4 the cost of making the larger circle.
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Which statement must be true? Two triangles placed side by side. Two sides each of the triangles are equal in length. The third
sladkih [1.3K]

It is impossible to determine the relationship between x and y from the question about the triangle. Hence,  the correct option is D. This is because none of the sides are labelled x or y from the information provided.

<h3>What are the relationships that exist between the sides of a triangle?</h3>

It is important to note that:

The side with the highest length is the side that is opposite the biggest angle.

It is also important to note that the angle that is least will always be opposite the side that is smallest.

Learn more about triangles at:
brainly.com/question/17335144
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7 0
2 years ago
What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
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