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elixir [45]
3 years ago
8

Help pleasesolve for x: -3x+3<6a. x>-1b. x<-1c. x<-3d. x>-3

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0
The answer is A.

I hope that helped let me know if i am correct!
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Solve x + y = 5 using matrices. 2x – y = 1 I have the answer, x = 2 and y =3, how do I phrase this as a matrices? (2,3)?
BartSMP [9]
X +y = 5

x = 5-y

---------------------

2x -y = 1

2•(5-y) -y = 1

10 -2y -y = 1

10 -3y = 1

-3 y = 1-10


-3y = -9

then you can divide it
y = -9/-3

y= 3


for x :

x + y = 5

x + (3) = 5
x= 5-3
x= 2


(x,y)

(2,3)
7 0
3 years ago
You solve a system of two linear equations by substitution. Your work results in a third equation, which leads you to conclude t
Amiraneli [1.4K]

Step-by-step explanation:

Here, in step format, is how to solve a system with three equations and three variables:

Pick any two pairs of equations from the system.

Eliminate the same variable from each pair using the Addition/Subtraction method.

Solve the system of the two new equations using the Addition/Subtraction method.

4 0
2 years ago
What is the product of 3x(x2 + 4)?<br> O x² + 3x +4<br> O 3x3 + 4<br> O 3x3 + 12x<br> 3x² + 12x
Svetradugi [14.3K]

Answer:

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Step-by-step explanation:

Given

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6 0
3 years ago
Subtract 766 from 941
Bess [88]
Your answer is 175.


Hope this helps!
7 0
3 years ago
Read 2 more answers
98-x2=0 solve this with the quadratic formula
Mars2501 [29]

Answer:

             x∈{-7√2, 7√2}

Step-by-step explanation:

98-x^2=0\\\\-x^2+98=0\\\\a=-1\,,\ \ b=0\,,\ \ c=98\\\\x_1=\dfrac{-0-\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{-\sqrt{4\cdot49\cdot2}}{-2}=\dfrac{-2\cdot7\sqrt{2}}{-2}=7\sqrt2\\\\x_2=\dfrac{-0+\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{2\cdot7\sqrt{2}}{-2}=-7\sqrt2

7 0
3 years ago
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