$Answer: \\ 4(2y - 20) + 2y = 720 \\ \Leftrightarrow 2(2y - 20) + y = 360 \\ \Leftrightarrow 4y - 40 + y = 360 \\ \Leftrightarrow 5y = 400 \\ \Leftrightarrow y = 80°$

8 0

3 years ago

How do I solve part b?

Minchanka [31]

Answer:

$x \approx 1.4$

Step-by-step explanation:

This problem gives one the following equation to model the graph of a line: ( $y=x^2-2$ ). The problem asks one to find the value of (x) when (y=0). Rather than using the graph, an easier way to solve this problem is to substitute (0) in for the value of (y) and then solve for (x) using inverse operations.

$y=x^2-2\\$

Substitute,

$0=x^2-2$

Inverse operations,

$0=x^2-2\\\\2=x^2\\\\\sqrt{2}=x$

Round:

$x \approx 1.4$

As one can see on the graph, this result is very close to the value at which the graph intersects the (x) axis. Thus, one can conclude that (x) does indeed approximately equal (1.4)

6 0

2 years ago

Find all real numbers x such that<br> x^4 ≤ 8x^2 − 16.

Maru [420]

$x^4 \leq 8x^2 -16\\
x^4-8x^2+16\leq0\\
(x^2-4)^2\leq0\\
x^2-4=0\\
x^2=4\\
x=-2 \vee x=2$

4 0

3 years ago