Answer:
Confidence Interval - 2.290 < S < 2.965
Step-by-step explanation:
Complete question
A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.
Solution
Given
n=50
x=23.33
s=2.6
Alpha = 1-0.80 = 0.20
X^2(a/2,n-1) = X^2(0.10, 49) = 63.17
sqrt(63.17) = 7.948
X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69
sqrt(37.69) = 6.139
s*sqrt(n-1) = 18.2

confidence interval:
(18.2/7.948) < S < (18.2/6.139)
2.290 < S < 2.965
The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.
Data;
- Mean rate = 0.3
- x = 50
- standard deviation = ?
<h3>Poission Rule</h3>
Using poission formula,

Let's substitute the values into the formula.
For 50 calls in 150 hours
For 150 hours = x = 0.3 * 150 = 45

b)
The probability the next call arrives after 2 hours.

c)
The number of calls recieved each day is recorded for 50 consecutive days.
for 50 days;

The mean = 360
The standard deviation is given as

The probability the sum of these 50 number is less than 356 is

Learn more on poission formula here;
brainly.com/question/7879375
63 in 4.5 hours
63 divided by 4.5 is 14 so
14 MPH would be your answer
I believe this is a problem dealing with proportions, so you could cross multiply and divide. so you would do 8/270 then x/72.5 , you cross multiply 72.5x8 which equals 580. then you divide that answer by 100 which equals 5.8 (:
Eleven Twentieths of the pie are left, so that's 11/20
Method to solve;
Since its given a 1/4 and a 1/5 it's easiest to convert these to twentieths (the lowest common multiple of 4 and 5)
So 1/4= 5/20
1/5 = 4/20
How much is eaten = 5/20 + 4/20 = 9/20
How much remains = Total (20/20) - How much eaten (9/20) = 11/20