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Natali [406]
3 years ago
10

I need help with these three questions can you help me?​

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

#2- A

#3- D

#4-1

Step-by-step explanation:

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Bradley's lemon cookie recipe calls for 2/3
viktelen [127]

Answer: 2 cups of sugar

Step-by-step explanation:

2/3 times 2 1/2

6/3

2

4 0
3 years ago
Nishi uses 6 bags of cat food every 5 months. How many bags of cat food does Nishi use in 12 months?
madam [21]
14.4bags of cat food
4 0
3 years ago
Read 2 more answers
A manager at a company that manufactures cell phones has noticed that the number of faulty cell phones in a production run of ce
ExtremeBDS [4]

Answer:

a) Poisson probability distribution

b) The probability of no faulty cell phones will be produced​ tomorrow is 0.1653

c) The probability of 3 or more faulty cell phones were produced in​ today's run is 0.2694

Step-by-step explanation:

Poisson distribution is used for independent events which occur at a constant rate within a given interval of time

The Poisson probability distribution formula is P(x; μ) = (e^-μ) (μ^x) / x! where

x is the actual number of successes that result from the experiment

e is approximately equal to 2.71828

μ  is the mean of the distribution

The number of faulty cell phones in a production run of cell phones is usually small and that the quality of one​ day's run seems to have no bearing on the next day

That means the probability of finding faulty phones in first day not depend on finding another days

Then the model might you use to model the number of faulty cell phones produced in one​ day is Poisson probability distribution

a) Poisson probability distribution

∵ The mean number of faulty cell phones is 1.8 per​ day

∴ μ = 1.8

∵ There is no faulty cell phones will be produced​ tomorrow

∴ x = 0

- Use the formula above to find the probability

∵ P(0 ; 1.8) = (e^-1.8) (1.8^0) / 0!

- Remember 1.8^0 = 1 and 0! = 1

∴ P(0 ; 1.8) = (e^-1.8)(1)/(1)

∴ P(0 ; 1.8) = 0.1653

b) The probability of no faulty cell phones will be produced​ tomorrow is 0.1653

∵ The mean number of faulty cell phones is 1.8 per​ day

∴ μ = 1.8

∵ There is 3 or more faulty cell phones were produced in​ today's run

∴ x ≥ 3

∵ P(x ≥ 3) = 1 - P(x = 0) - P(x = 1) - P(x = 2)

- Let us find P(1 ; 1.8) and P(2 ; 1.8)

∵ P(1 ; 1.8) = (e^-1.8) (1.8^1) / 1!

∵ 1.8^1 = 1.8

∵ 1! = 1

∴ P(1 ; 1.8) = (e^-1.8)(1.8)/(1)

∴ P(1 ; 1.8) = 0.2975

∵ P(2 ; 1.8) = (e^-1.8) (1.8^2) / 2!

∵ 1.8^2 = 3.24

∵ 2! = 2

∴ P(2 ; 1.8) = (e^-1.8)(3.24)/(2)

∴ P(2 ; 1.8) = 0.2678

Substitute them in the rule above

∵ P(x ≥ 3 ; 1.8) = 1 - 0.1653 - 0.2975 - 0.2678

∴ P(x ≥ 3 ; 1.8) = 0.2694

c) The probability of 3 or more faulty cell phones were produced in​ today's run is 0.2694

7 0
3 years ago
A triangle has sides with lengths of 5x-7,3x-4 and 2x-6. What is the perimeter of the triangle?
boyakko [2]
The perimeter is the sum of all the sides, so P = (5x -7) + (3x-4) + (2x -6). Then group like terms so you have p = 5x + 3x + 2x -7-4-6 and end up with P = 10x - 17
7 0
3 years ago
Please help need answer fast will give brainliest
Maslowich
A) (2, 7) (0, 3)

B) (1,5) (3, 3) 

C) inconsistent because it starts to go down.

D) (0,3) (1, 5) (2,7) (3,3)


I hope this helped
    
4 0
3 years ago
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