The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
<h3>How to determine the legs of the triangle?</h3>
The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
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Answer:
Step-by-step explanation:
5) x + 5.4 < -1.6
x < -1.6 - 5.4
x < -7
6) x + 7.5 > -2.5
x > -2.5 - 7.5
x > -10
7) 3 ≤ 1/3 + x
x ≥ 3 - 1/3
x ≥ 5/3
Answer:
x=(k+3)/y
Step-by-step explanation
First, we simplify by adding 3 to both sides of the equation
xy-3+3=k+3
Now it's xy=k+3
To get x we divide both sides by y
So x=(k+3)/y
Answer:
no more than 8.8 pounds
Step-by-step explanation: