we know that
the rate of a linear equation is equal to the slope
Step 1
Find the bear’s average heart rate when it’s active
Let
A(1.5,90) B ( 2,120)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(120-90)/(2-1.5)=30/0.5
m=60 heartbeats/min
therefore
the answer part a) is
the bear’s average heart rate when it’s active is 60 heartbeats/min
Step 2
Find the bear’s average heart rate when it’s hibernating
Let
A(1.5,18) B ( 2,24)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(24-18)/(2-1.5)=6/0.5
m=12 heartbeats/min
therefore
the answer part b) is
the bear’s average heart rate when it’s hibernating is 12 heartbeats/min
V = speed of light = 3 x 108 m/s
d = distance = 384000 x 103 m = 3.84 x 108 m
time taken = t = d/V = 3.84 x 108 /(3 x 108 ) = 1.28 sec
Answer:
Step-by-step explanation:
I'm sure he was making a joke at the expense of people who rely on mathematics rather than common sense. It is funny, but then Twain was a remarkably funny author..
The problem is that the comparison is apt using some sort of proportion, but it is absurd to think that the land holding the river would also shrink a proportional amount.
The river reached a minimum (presumably) in 1875 by cutting out all the loops that were there in 1700. The Mississippi was then a straight line from it's beginning to its delta on the gulf of Mexico. It could not get any shorter. Still, Twain managed to get laughs with his whimsical humor.
Thanks for posting. This made my evening.
