Question

Aaron is using a special beaker in science that is a cylinder with a radius of 2 cm and a height of 3 cm on top of a cylinder that has a radius of 6 cm and a height of 4 cm. What is the volume of this beaker? Use 3.14 for pi.
A) 339.12 cm³
B) 357.96 cm³
C) 489.84 cm³
D) 508.68 cm³

Answer 1

Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.

We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.

Given, π = 3.14

Beaker 1:

Radius (r₁) = 2 cm
Height (h₁) = 3 cm

Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³

Beaker 2:

Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³

Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³

Answer 2

So we just computate the volumes of 2 cylinders and add them Vcylinder=hpir^2 top one is r=2 and h=3, so V=3pi2^2 or 3pi4 or 12pi cm^3 bottom one is r=6 and h=2 so V=4pi6^2 or 4pi36 or 144pi cm^3 total 12pi+144pi=156pi=total volume aprox pi=3.14 total volume=489.84 C is answer