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4 years ago

List the numbers 56.01 56.011 56.10 from least to gratest

Mathematics

1 answer:

iogann1982 [59]4 years ago

5 0

They are all very close numbers. But very simple to place in order.
56.01 56.011 56.10
In order = 56.01 56.011 56.10

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Sin4u=2sin 2u cos 2u

yKpoI14uk [10]

Answer:

If you've learnt sin(A+B) = sinAcosB + cosAsinB,

sin(4u)

= sin(2u+2u)

= sin(2u)cos(2u) + cos(2u)sin(2u)

= 2 sin(2u) cos(2u).

4 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- see attachment for the generated data

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Can a linear function have two x-intercepts?

Umnica [9.8K]

At most it will have 1 x-intercept

5 0

3 years ago

Read 2 more answers

If u answer corectly (i know the answer already) ill paypal u 3 dollars

Helen [10]

Answer:

Park A

Step-by-step explanation:

Park b in decimal: 17 ÷ 8 = 2.125 miles

Park A is closer

7 0

3 years ago

Read 2 more answers

Which graph represents an equation in the form =? Please help me!!

Genrish500 [490]

That's a question about graphs.

In the Cartesian coordinate system, we have two axes: The x-axis (horizontal) and the y-axis (vertical).

When we want to represent a equation in the cartesian coodinate system, we associate a point in the x-axis and other in the y-axis. The Cartesian coordinate is represented by (x, y).

To represent some equation in a graph, we need at least two points to draw a line that cross these 2 points.

For example: To represent the equation $y = x +1$ , let's replace the value of x:

When x = 0 → $y = 0 + 1 = 1$ . Therefore, the coordenate is (0, 1).

When x = 1 → $y = 1 + 1 = 2$ . Therefore, the coordenate is (1, 2).

Finally, if we draw a line tha cross these 2 points, we will have the graph that represents $y = x +1$ .

Now you know about it, let's solve our problem?

In that question, we should to find the graph that represents the equation $y = kx$ , but we don't know the value of k, so what should we do? It's easy:

k is a constant. That means that the value of k never changes. Now, let's analyze a specific case:

If x = 0, so y = 0 as well. But why? We know that any number multiplied by 0 is equal 0. Therefore:

When If x = 0 → $y = 0 \times k = 0$ . So, this graph cross the coordinate (0,0).

With the informations that the problem give to us, these are the unique things that we can find, but that's enough.

When we look at the options, just the second graph have a line that cross the coordenate (0, 0). Therefore, the correct answer is the graph below:

I hope I've helped. :D

Enjoy your studies! \o/

8 0

3 years ago