Answer:
2500000000
Step-by-step explanation:
→ Multiply 1 by 25000
1 × 25000 = 25000
→ Convert into metres
2500000
→ Convert into centimetres
2500000000
Answer:
a) fog(x) = (x-2)⁴ +4
b) (g o f) (x) = x⁴ + 2
c) hog(x) = 
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the function
f(x) = x⁴+4 , g(x) = x-2 , h(x) = √x
f o g (x) = f(g(x))
= f(x-2)
= (x-2)⁴ +4 (∵ f(x) = x⁴ +4))
fog(x) = (x-2)⁴ +4
<u><em>Step(ii):-</em></u>
(g o f) (x) = g(f(x))
= g(x⁴ +4)
= x⁴ +4 -2 ( ∵ g(x) = x-2)
= x⁴ + 2
(g o f) (x) = x⁴ + 2
<u><em>Step(iii)</em></u>:-
hog(x) = h(g(x))
= h(x-2)
=
hog(x) =
Answer:
x - 2
Step-by-step explanation:
(x + 2)(x - 2) = x^2 - 4
Answer:
<h2><em>
112cm²/sec</em></h2>
Step-by-step explanation:
Area of a square is expressed as A = L² where L is the length of one side of the square.
The rate of change of area will be expressed using chain rule as;
dA/dt = dA/dL * dL/dt where;
dL/dt is the rate at which the side length of the square is decreasing.
Given L = 7cm, dL/dt = 8cm/sec and dA/dL = 2L
dA/dL = 2(7)
dA/dL = 14cm
Substituting the given value into the chain rule expression above to get the rate of change of the area of the square, we will have;
dA/dt = dA/dL * dL/dt
dA/dt = 14cm * 8cm/sec
dA/dt = 112cm²/sec
<em>Hence, the rate of change of the area of the square when the side length is 7 cm is 112cm²/sec</em>
<em></em>
