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Sunny_sXe [5.5K]
3 years ago
10

Can someone help me please? Am I right or no?

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0
The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²
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4x – 9 = 2x + 15 can someone explain the system used to answer this question
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The system is comprised of two processes
that go on at the same time:

       #1). Do what ever you want to, to get 'x'
               on one side of the equation, and
               everything else on the other side.
       #2). Whatever you do to one side of the equation,
               you must immediately do the same thing to the
               other side.

That's the system.

Here's how it works:  (I can't believe you're in high school math
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You said that                               4x - 9  =  2x + 15                   
and you need to find
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Subtract  2x  from each side:    2x - 9  =           15

Add  9  to each side:                 2x        =            24

Divide each side by  2 :              x        =             12 .  

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