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Sunny_sXe [5.5K]
2 years ago
10

Can someone help me please? Am I right or no?

Mathematics
1 answer:
Juliette [100K]2 years ago
4 0
The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²
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Answer:

the plane would fall and crash at 150mph

Step-by-step explanation:

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The equation V= 1/3 Bh gives the volume V of a pyramid, where B is the area of the base and h is the height. Solve this equation
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times both sides by 3
3V=Bh
divide both sides by h
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2 years ago
If a train traveled at 50 meters within 120 seconds, what is its speed?
Alja [10]

Answer:

v = 0.416 m/s

Step-by-step explanation:

Give that,

Distance covered by a train, d = 50 m

Time taken, t = 120 s

We need to find the speed of a train. The formula for speed of an object is equal to the total distance covered divided by total time taken. It can be given by :

v=\dfrac{d}{t}\\\\v=\dfrac{50\ m}{120\ s}\\\\v=0.416\ m/s

So, the speed of a train is 0.416 m/s.

3 0
2 years ago
You have a 10 by 24 piece of cardboard. You are going to cut squares of equal size from each corner, and fold up the sides to ma
densk [106]

Answer:

  10-2x

Step-by-step explanation:

If x is the length of one side of the square, the total width of the cardboard has two squares cut from it. The amount of width remaining is the width of the box. Since the original width of the cardboard is 10, the width of the box is ...

  10 -2x

8 0
2 years ago
The path of a skateboarder can be modeled by the equation (x – 3)2 = –8(y – 8), where distance is in feet and air resistance is
yKpoI14uk [10]

The maximum height and horizontal distance is required.

Maximum height 8 feet; horizontal distance 16 feet

The given path is (x-3)^2=-8(y-8)

If the skateboarder jumps at x = 0 she will land at y = 0. However there will be at horizontal displacement.

(x-3)^2=-8(0-8)\\\Rightarrow (x-3)^2=8^2\\\Rightarrow x-3=\pm 8\\\Rightarrow x-3=8\\\Rightarrow x=11

or

x-3=-8\\\Rightarrow x=-5

The distance between -5 and 11 is 11-(-5)=16

Middle point would be \dfrac{16}{2}=8 from -5.

-5+8=3

So, x=3

The maximum height will be

(3-3)^2=-8(y-8)\\\Rightarrow y-8=0\\\Rightarrow y=8

The maximum height is 8 feet and the horizontal distance is 16 feet.

Learn more:

brainly.com/question/25227606

brainly.com/question/13103131

6 0
3 years ago
Read 2 more answers
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