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3 years ago

15

A football player tosses the ball through the air to a teammate. Could the path of the ball be described by the equation y = 0.5

x2 + 0.3x + 2?

1 answer:

RSB [31]3 years ago

4 0

Answer:

Step-by-step explanation:

No; the graph for the path of a ball must be a parabola that opens downward, so if the equation is in the form y = ax2 + bx + c, a must be negative.

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I don't think I'm doing this right heeellppp

Feliz [49]

Any locker with a number that is a multiple of 8, 12, and 75 will contain all three animals.

The least common multiple of these three numbers is

$\mathrm{lcm}(8,12,75)=600$

and so any multiples of 600 between 1 and 3500 will contain all three animals. These are 600, 1200, 1800, 2400, and 3000.

Why is the LCM 600? You can determine that using the prime factorizations of the three given numbers:

$8=2^3$
$12=2^2\times3$
$75=3\times5^2$

The LCM can be obtained by multiplying as many prime numbers together as are needed to contain the prime factorizations of the three numbers. This is obtained with

$2^3\times3\times5^2=8\times3\times25=600$

(at least three 2s to get the 8; at least one 3 and two of the previous 2s to get 12; and at least two 5s along with the previous 3 to get 75)

8 0

3 years ago

An insurance policy on an electrical device pays a benefit of 4000 if the device fails during the first year. The amount of the

lora16 [44]

Answer:

Expected benefit under this policy = $ 2694

Step-by-step explanation:

Given - An insurance policy on an electrical device pays a benefit of

4000 if the device fails during the first year. The amount of the

benefit decreases by 1000 each successive year until it reaches 0.

If the device has not failed by the beginning of any given year, the

probability of failure during that year is 0.4.

To find - What is the expected benefit under this policy ?

Proof -

Let us suppose that,

The benefit = y

Given that, the probability of failure during that year is 0.4

⇒Probability of non-failure = 1 - 0.4 = 0.6

Now,

If the device fail in second year , then

Probability = 0.6×0.4

If the device fail in third year, then

Probability = 0.6×0.6×0.4 = 0.6² × 0.4

Going on like this , we get

If the device is failed in n year, then

Probability = 0.6ⁿ⁻¹ × 0.4

Now,

The probability distribution is-

Benefit , x 4000 3000 2000 1000 0

P(x) 0.4 0.6×0.4 0.6² × 0.4 0.6³ × 0.4 1 - 0.8704

(0.4) (0.24) (0.144) (0.0864) (0.1296)

At last year, the probability = 1 - (0.4+ 0.24+ 0.144+ 0.0864) = 1 - 0.8704

Now,

We know that,

Expected value ,

E(x) = ∑x p(x)

= 4000(0.4) + 3000(0.24) + 2000(0.144) + 1000(0.0864) + 0(0.1296)

= 1600 + 720 + 288 + 86.4 + 0

= 2694.4

⇒E(x) = 2694.4 ≈ 2694

∴ we get

Expected benefit under this policy = $ 2694

5 0

3 years ago

10 十w=-9<br> I’m very confused please help

cricket20 [7]

Answer:

w = -19

Step-by-step explanation:

10 + w = -9

<u>-10 -10</u>

w = -9 - 10

w = -19

8 0

3 years ago

Read 2 more answers

WILL MARK BRANLIEST IF GOTTEN RIGHT

Mamont248 [21]

Answer:

The last choice. The red one

Step-by-step explanation:

I'm just guessing at this point. But, by the looks of it, red does seem like it would be correct. Again, this is just a guess. So, if it's wrong I'm so sorry. Have a lovely day.

3 0

3 years ago

Jackson bought 3 pounds of candy for $9.60.

Neporo4naja [7]

Answer:

320 cents per pound

or

$3.20 per pound

Step-by-step explanation:

Divide dollars by pounds

$9.60/3 = $3.20 per pound

Since it asks for the price of candy in cents per pound, multipy 3.20 by 100.

3.20 x 100 = 320 cents

320 cents per pound.

3 0

2 years ago

Read 2 more answers