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Damm [24]
3 years ago
10

Of the 84 parents who attended a meeting at a school, 35 volunteered to supervise children during the school picnic and 11 volun

teered both to supervise children during the picnic and to bring refreshments to the picnic. If the number of parents who volunteered to bring refreshments was 1.5 times the number of parents who neither volunteered to supervise children during the picnic nor volunteered to bring refreshments, how many of the parents volunteered to bring refreshments
Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

The number of parents who volunteered to bring refreshments is 16.

Step-by-step explanation:

The information provided is:

N = 84

n (S) = 35

n (S ∩ R) = 11

n (R) = 1.5 × n (S' ∪ R')

Compute the value of n (S ∪ R) as follows:

n(S\cup R)=n(S)+n(R)-n (S\cap R)\\\\n(S\cup R)=n(S)+[1.5(N-n(S\cup R)]-n (S\cap R)\\\\n(S\cup R)=n(S)+1.5N-1.5n(S\cup R)-n (S\cap R)\\\\2.5n(S\cup R)=n(S)+1.5N-n (S\cap R)\\\\2.5n(S\cup R)=35+(1.5\times84)-11\\\\2.5n(S\cup R)=150\\\\n(S\cup R)=\frac{150}{2.5}\\\\n(S\cup R)=60

Now compute the value of n (R) as follows:

n (R) = 1.5 \times  n (S' \cup R') \\\\n (R) = 1.5 \times  [N-n (S \cup R)]\\\\n (R) = 1.5 \times  [84-60]\\\\n(R)=16

Thus, the number of parents who volunteered to bring refreshments is 16.

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An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 140 students in th
Arlecino [84]

Answer:

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

140 students, so n = 140

B or better are grades of A or B.

5% earn As, 23% earn Bs, so p = 0.05 + 0.23 = 0.28

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.2056

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.3544

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

7 0
3 years ago
Mr. Morales purchases 6 boxes of pencils, 12 boxes of pens, and 4 cases of notebook paper for his classroom. Each box of pencils
Darina [25.2K]

Answer:

$522.60

Step-by-step explanation:

               pencils:  $4.10 * 6             ===> $24.60

                  pens:  $6.50 * 12           ===> $78

notebook paper:  $105 * 4              ===> $420

pencils + pens + notebook paper = total cost

24.60 + 78 + 420 = 522.60

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Solve the system of x minus 2y equals negitive 2 and negitive x plus y equals 3
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Answer:

123

Step-by-step explanation:

I got it with the calculator

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C) -7

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I think the best option would be C
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