3 years ago

May someone help? show my work too

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Stfertsrydrydstgfthgsy

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<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=

KiRa [710]

$e ^{2x} = ln5$

Solve for the real domain

$e ^{2x} = ln(5)$

if $f(x) =g(x),$ then $ln(f(x))= ln(g(x))$

$ln(e ^{2x} ) = ln(ln(5))$

Solve : $ln(e ^{2x} ) = ln(ln(5))$

use the logarithmic definition :

$ln(e^{f(x)} ) = f(x)$

$ln(e^{2x} ) = 2x$

$2x=ln(ln(5))$

Divide both sides by 2 :

$\frac{2x}{2} = \frac{ln(ln(5))}{2}$

$x= \frac{ln(ln(5))}{2}$

hope this helps!

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3 years ago

F(x) =1/3x how do you graph it

Delvig [45]

Answer:

draw a straight line with a ruler through the points (0,0) and (3,1)

Step-by-step explanation:

since your equation is linear, you need to use a ruler to graph, put in 0 and 3 to get 0 and 1, respectively, and draw a line through the two points on a graph

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3 years ago

Given the following function and given domain, what is the range? f(x) = x2 +1; {-2, 1, 0, 2}

BigorU [14]

Answer:

answer is zero in the following

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2 years ago

Read 2 more answers

Question is in the picture please show work

postnew [5]

Answer: