8 is the answer to your question
Answer:
C. The x-coordinate of the vertex must be 6
Step-by-step explanation:
The parabola intercepts the x-axis when y = 0.
Therefore, if the quadratic equation has the points (2, 0) and (10, 0) then the x-intercepts or "zeros" are x = 2 and x = 10.
The x-coordinate of the vertex is the midpoint of the zeros.

Therefore, the solution is option C.
<u>Additional Information</u>
The leading coefficient of a quadratic tells us if the parabola opens upwards or downwards:
- Positive leading coefficient = parabola opens upwards
- Negative leading coefficient = parabola opens downwards
We have not been given this information and so therefore cannot determine the way in which it opens.
As we do not know the way in which way the parabola opens, we cannot determine if the parabola will have a negative or positive y-intercept.
We have not been given the full quadratic equation, and so we cannot determine if the parabola is wider (or narrower) than the parent function.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Answer:
5.5%
Step-by-step explanation:
Given data
Simple interest = $137.50
Principal= $500
time = 5 years
We want to find the rate R
Simple interest= PRT/100
137.50 = 500*R*5/100
137.50=2500R/100
cross multiply
137.5*100= 2500R
13750= 2500R
divide both sides by 2500
R= 13750/2500
R=5.5%
Hence the rate is 5.5%
Answer:
Step-by-step explanation:
left side is 120 word per minute and the right side is 185 word per minute