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Allushta [10]
3 years ago
15

X^+5x+8=0 What is the answer to this question

Mathematics
1 answer:
ira [324]3 years ago
5 0

Step-by-step explanation:

X^+5x+8=0

x^2+5x=-8 kajvdvdhxjxjjxjxjxjxhx

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Help me with this please (sorry for the bad picture) ​
Elenna [48]

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4 0
3 years ago
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Need help with this question
velikii [3]
All you have to do is plug in the given x values. your first equations would read:

f(-3) = 2^(-3)
f(-2) = 2^(-2)
f(-1) = 2^(-1)

these can be solved by moving decimal points or entering them into a calculator. regardless of the method, your answers are:

f(-3) = 0.002
f(-2) = 0.02
f(-1) = 0.2

so just repeat that process to fill in the rest of your table. to graph it, you'll use them as normal (x, y) points:

(-3, 0.002)
(-2, 0.02)
(-1, 0.2)

the graph might be a little difficult, working with such small values, but precision isn't totally important--0.002 will be super close to 0, 0.02 will be slightly further, 0.2 will be slightly further. the smaller values don't matter as much graphically and you'll recognize the graph of a growing exponential as you graph more of the table.
7 0
3 years ago
4,650 Rounded to the hunred
Zielflug [23.3K]
4650
 ^ This is the hundreds place

Look at the number after it, if it's 5 or more we round up, if it's 4 or less we round down.

The number is 5, so we round up to 4700.
7 0
3 years ago
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According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random
Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.39, n = 100

Then

s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

5 0
2 years ago
Find the volume of and shape 3 4 4 6 2
Dvinal [7]
Umm is it a multiple choice question?
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