Here is one <span>Jake’s salary depends on the number of hours he works.
The independent variable is the number of hours and the dependent variable is salary.
Let x = the number of hours worked
Let y = Jake's salary
The set of ordered pairs {(1, 10), (2, 20), (3, 30), (4, 40), (5, 50)} can be used to represent
the function, assuming Jake earns $10 per hour.
</span>
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
Answer:
0.83,0.50
Step-by-step explanation:
Since there are 2 digits in 83, the very last digit is the "100th" decimal place.
So we can just say that .83 is the same as 83/100.
So your final answer is: .83 can be written as the fraction
67,239; 28912/5.56= 5,200 miles per hour and then multiply that by 12.93
46.085 to the nearest hundredth is 46.09 hope it helped ;)
