<span>What are the zeros of f(x) = x2 – 8x + 16?
</span>
let the function f(x) = 0
so
x^2 – 8x + 16 = 0
(x - 4)^2 = 0
x - 4 = 0
x = 4
hope it helps
Answer:
No
Step-by-step explanation:
Four times d to the third minus ten
Answer:
(-8, -4) is the solution
Step-by-step explanation:
Determine whether or not (-8, -4) is a solution to this system. It is a solution if we can substitute -8 for x and -4 for y in both equations and find that both equations are true:
2(-8) = 5(-4) + 4 TRUE
3(-8) - 2(-4) = -16 TRUE
So (-8, -4) is a solution to the given system.
Check out the second possible solution in the same way:
2(8) = 5(4) + 4 FALSE
Check out the third possible sol'n in the same way:
2(-4) = 5(4) + 4 FALSE
Check out the fourth in the same way:
2(4) = 5(8) + 4 FALSE
So we conclude that (-8, -4) is the sole solution to the given system.
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