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2 years ago

Similar triangles are congruent. a. - always b. - sometimes c. - never

Mathematics

2 answers:

scoray [572]2 years ago

8 0

Answer:

Similar triangles are sometimes congruent.

Step-by-step explanation:

<em>" Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size "</em>

We can consider two triangle such that the measure of all the angles are equal but the sides of one triangle is three times the side of the other triangle in such a case the triangles are not congruent but they are similar.

<em>Hence, similar triangles are sometimes congruent.</em>

irina1246 [14]2 years ago

5 0

<span>Two triangles with two sides and a non-included angle equal may or may not be congruent. If two angles on one triangle are equal, respectively, to two angles on another triangle, then the triangles are similar, but not necessarily congruent.</span>

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Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

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Answer: carnation $2.50; rose $3.00

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2 years ago

Sarah spends of her monthly take-home pay on rent, food, and clothing. If she earns $1,830 in take-home pay each month, how much

frosja888 [35]

Sarah spendings

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1 year ago

How to turn 20/10 into a mixed number

Lady_Fox [76]

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3 years ago

Read 2 more answers

A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$