Answer: B.) 62
sum of interior angles of quadrilateral = 360
lines DB and DA are tangent to the circle, so they're at a right angle to the lines OB and OA respectively. so to find mBOA = 360 - 56 - 90 - 90
so mBOA = 124
mBCA = (1/2)mBOA
mBCA = (1/2)(124)
mBCA = 62°
Point A is in Quadrant I where the x and y are both positive.
Point B lies in between Quadrants II and III. Or it lies on the x-axis (If this is an option).
i dont know. Im sorry about that.
Answer:
56.6 °
Step-by-step explanation:
For a RIGHT triangle cos (x ) = adjacent leg / hypotenuse
cos (x) = 4.4 / 8
arc cos (4.4/8) = 56.63 ° = ~ 56.6°
