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Ber [7]
3 years ago
12

What is the solution to the system of equations below?

Mathematics
2 answers:
leonid [27]3 years ago
5 0
B
( 3 , 9 )

B i s    t h e    a n s w e r 
Ivenika [448]3 years ago
3 0

A (9,3) is the correct answer on edge

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If a Customer places an order for $47.36 and it’s late, then how much would the customer be refunded if the refund is 20% on the
Serggg [28]
$9.47

I just multiplied the total by the refund percentage to get that number. It’s just like finding a tip.
6 0
3 years ago
Write the equation of a line PERPENDICULAR to the line y = 3x + 2 that passes through
Dominik [7]

Answer:

7

Step-by-step explanation:

how 7 because the digris that know be a last number and can be sure the meaning are complecataed thats tight

7 0
3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
3 years ago
How many solutions does this system of equations have?
guajiro [1.7K]

Answer:

1 solution

Step-by-step explanation:

A system of linear equations has no solution when the graphs are parallel.

7 0
3 years ago
Which expression is equivalent to 6x^2 + 13x + 5?
hodyreva [135]

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

... C (2x+1)(3x+5)

_____

If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

3 0
3 years ago
Read 2 more answers
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