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3 years ago

What is the solution to the system of equations below?

Mathematics

2 answers:

leonid [27]3 years ago

5 0

B
( 3 , 9 )

B i s t h e a n s w e r

Ivenika [448]3 years ago

3 0

A (9,3) is the correct answer on edge

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What is 40+70 answer fast!!!!

IceJOKER [234]

Answer:

110

Step-by-step explanation:

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3 years ago

Read 2 more answers

The scheduled arrival time for a daily flight from Boston to New York is 9:35 am. Historical data show that the arrival time fol

Lady_Fox [76]

Answer:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean is:

$M = \frac{a+b}{2}$

The standard deviation is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

Arrival time of 9:18 am and a late arrival time of 9:41 am.

9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.

Mean:

$M = \frac{a+b}{2} = \frac{0+23}{2} = 11.5$

Standard deviation:

$S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(23 - 0)^{2}}{12}} = 6.64$

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

8 0

3 years ago

Evaluate the following: −3 − (−2). (5 points) Question 1 options: 1) −5 2) −1 3) 1 4) −6

Ganezh [65]

Answer:

2) -1

Step-by-step explanation:

it is easy

we have to first open the brackets, as it is ' - ' we have to change the sign to opposite of that of the number in the bracket and then solve it.

so the number 2 is having negative sign, we make it positive. this rule is applied only when there is a negative sign and a bracket is there.

-3-(-2)

-3+2

=-1

7 0

4 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$