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3 years ago

What is the actual length of the flower garden

Mathematics

1 answer:

MrMuchimi3 years ago

4 0

Width= wlength = l=w+5 Area = l * w 104 =(w+5) * w w2 +5w -104 =0 (w+13)(w-8)=0w=13 and w=8so width =8length=13

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Help me please ❤️❤️ geometry winter packet

Artemon [7]

The answer is b,a,c
the reason I know this is because the angle opposite to the largest side is the greatest angle, the angle across from the smallest side is the smallest angle

6 0

3 years ago

after allowing 20 percent discount on the marked price of a radio 15 percent vat is levied on it , if its price become rs 22080

Kamila [148]

Answer:

Step-by-step explanation:

Hello, let's say that the price was P, a real number.

After 20% discount it become P - 20% * P = P* (1-20%) = P * (1 - 0.2)

= P * 0.8

And then we take 15% for the VAT, the new price become P * 0.8 * ( 1 + 15%)

= P * 0.8 * 1.15

And this is equal to 22080, so

P * 0.8 * 1.15 = 22080

and the amount of the VAT is P *0.8 * 0.15

$=\dfrac{22080}{1.15}*0.15=2880$

Hope this helps.

Thank you.

5 0

3 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.