Area enclosed in
radians =$\pi r^2$
so area enclosed in $\theta$ radians=$\theta \times \frac{\pi r^2}{2\pi}= \frac{1}2\theta r^2$
does this answer your question?
A machine can print 30 t-shirts in 1 min., because the ratio of time to shirts is 300 shirts per 10 mins and 30 per 1 is 1/10 of that.
BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
Answer:
John's standard z-score is 2.383
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = $810
John's rent = $1370
Population standard deviation, σ = $235
Formula:

Putting all the values, we have

John's standard z-score is 2.383
C i think sorry if it is wrong