Image 1.1 -
Stomata are little moth-like structures in leaves, that, when open, allow the exchange of gases between the plant and the exterior.
Answer:
B.
Image 1.2 -
Without the existance of stomata, the process of transpiration wouldn't be possible if there weren't structures thata allowed the exchange of gases.
Answer:
A.
Image 2 -
So, we can elminate plants because they can photosynthesise; bacteria because they are prokaryotes and can photosynthesise; archaea because they are prokaryotes; hat leaves us with animals and fungi because these cannot photosynthesise and are both eukaryotes.
But, we cannot skip information. It is also said that the organism found has a cell wall, and animals do not have cell walls.
Answer:
C.
Image 4 -
Option 1 = cilia
Option 2 = flagella
Option 3 = pseudopods
Option 4 = pili (they're a meant to attacht to surfaces only bacteria)
Image 5 -
Runner stems are those that grow horizontally, therefore the fourth image with the long horizontal stems.
Rhizome stems are underground stems that can form roots or shoots through their nodes. Therefore, the third image with white background (the one with 2 drawn plants).
Tuber stems are large underground (mostly) structures used as storages for the plant. Therefore, this corresponds to the first image (the one with the white background.
Bulb stems are short and "bulby" stems, whith thick, leaves. Therefore, the second image (the one with the grass background).
Hope it helped,
BioTeacher101
That fact can be explained by the similarity in their genes.
Dogs and coyotes are from the same class, family and genus (Mammalia, Canidae, Canis).
This is almost enough for their offspring to be viable. But if the DNA is similar (which it is) offspring the chances of viable and fertile offspring is high almost at 100%.
Hope it helped,
Happy homework/ study/ exam!
Answer:
The males can only either be black or orange
Explanation:
There can be no male calico because for an offspring to be a calico the two codominant alleles must each be carried on the two X chromosomes and in the males, there is the presence of just one X chromosomes, thus they can either be black or be orange. For the females, the can only be black if they carry the black allele on both X chromosomes, the same goes for the orange.
Parents XB Y
XB XBXB <u>XBY</u>
XC XCXB <u> XCY </u>
XBY- black male
XCY- orange male
Answer:
38 ATP
Explanation:
On complete oxidation of one molecule of glucose yields 38 ATP. Break up of energy production is given below:
- During glycolysis 2 ATP and 2 NADH is produced.
- During formation of Acetyl CoA, 2 NADH is produced.
- During Citric Acid Cycle, 2 ATP, 6 NADH, 2 FADH₂ are produced.
Finally during Electron transport chain, reduced coenzymes NADH and FADH₂ oxidised to release ATP. Each NADH produce 3ATP and each FADH₂ produces 2 ATP. Altogether 10 NADH is produced during entire process of cellular respiration which yield 30 ATP and 2 FADH₂ yields 4 ATP. Therefore, on complete oxidation of one molecule of glucose yields 38 ATP.
