4 years ago

Using the greatest common factor for the terms, how can you write 80 + 32 as a product?

Mathematics

1 answer:

Vadim26 [7]4 years ago

6 0

16(5+4) is 80+32 as a product using the GCF

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(Here's a free one )

ivolga24 [154]

Answer:

5/6

Step-by-step explanation:

5 0

4 years ago

A student clamied that the number -4 is not rational because it is not a ratio of two integers. Do you agree or disagree?

RideAnS [48]

Answer:

I disagree.

Step-by-step explanation:

An integer is a whole number ranging from -2,147,483,648 to 2,147,483,647.

A ratio of two integers with -4 could be -4/1, so -4 is a rational number.

8 0

3 years ago

Read 2 more answers

Which statement is true

AURORKA [14]

maybe the fourth one

7 0

4 years ago

Elizabeth plans on buying a new car for $25,000. The model she is looking at depreciates at a rate of 8.5% per year. Elizabeth p

alisha [4.7K]

Answer:

(25,000)(0.915)^t > 15,000

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago