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3 years ago

Five times the sum of a number and six is equal to three times the difference of a number and ten.

Mathematics

1 answer:

romanna [79]3 years ago

6 0

Answer: 6x + 6

Step-by-step explanation:x = the number 5x + (x + 6) {five times the number added to the sum of the number and six} = 5x + x + 6 {took out parentheses}

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Please help me again. I am begging you guys.

dangina [55]

Answer:

I=$ 198

Step-by-step explanation:

I=PRT

P=1200

T=3

R=5.5% = 0.055

I=1200*0.055*3= 198

5 0

3 years ago

2 questions

Alekssandra [29.7K]

Answer:

1. A. $33 loss

2. B

Step-by-step explanation:

1. -26 - 11 - 9 +13 = -33

2. B is the only graph in which the Whole Numbers do not contain a negative or decimal (which are not WNs)

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

Can you please use my for gauth code GHD989

viva [34]

Answer:

what........???????............

4 0

2 years ago

If x = 7, what is the value of the expression above?

givi [52]

if x= 7 what is the value of x-4

7 - 4

if y=3 what is the value of 8y

8 x 3

= 24

if x=7 what is the value of 3x-4

(3 x 7) - 4

= 17

if x=7 and y=3 what is the value of 2x-7y

(2 x 7) -(7 x 3)

= - 7

if x=7 and y=3 what is the value of 4y-X

(4 x 7) - 3

= 25

Hope this helps

8 0

3 years ago