Answer:RTGrg
Step-by-step explanation:just need points lol sorry
Answer:
A) 1.3*10¹
B)7*10⁰ - Actually I am not very sure if it is required to write 10⁰. I normally don't write 10⁰ (When I solve problems in physics if the answer for example is 7 I just write 7 not 7*10⁰). But if you check on Google 10⁰ has been mentioned
C)1.4*10¹
D)1.2*10¹
Step-by-step explanation:
For any number when you express it in a scientific notation, You should make sure that the number (for example : X) X which is going to be multiplied with a power of 10 (for example:10³,10⁴10¹⁰ etc), X should be between 1 and 10
This might sound very complicated so I can give you an example to simplify
Let's take 1.3*10¹
In this case X is 1.3
This means X*10¹
The number X is being multiplied with the power of 10(example:10¹,10²,10⁰,10⁹ ,etc) .In the above case X is being multiplied with 10¹.
Now this number X should be between 1 and 10.(Including 1)
Scientific notation= X*power of 10
where x>=1 & x<10
That is the explanation
Hope it helps
If you think my explanation is a bit complicated
you can ask me again
now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus 
.
so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.
![\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bsum%20of%20a%20finite%20geometric%20sequence%7D%5C%5C%5C%5CS_n%3D%5Csum%5Climits_%7Bi%3D1%7D%5E%7Bn%7D%5C%20a_1%5Ccdot%20r%5E%7Bi-1%7D%5Cimplies%20S_n%3Da_1%5Cleft%28%20%5Ccfrac%7B1-r%5En%7D%7B1-r%7D%20%5Cright%29%5Cquad%20%5Cbegin%7Bcases%7Dn%3Dn%5E%7Bth%7D%5C%20term%5C%5Ca_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5Cr%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C----------%5C%5Ca_1%3D2000%5C%5Cr%3D1.1%5C%5Cn%3D4%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5CS_4%3D2000%5Cleft%5B%20%5Ccfrac%7B1-%281.1%29%5E4%7D%7B1-1.1%7D%20%5Cright%5D%5Cimplies%20S_4%3D2000%5Cleft%28%5Ccfrac%7B-0.4641%7D%7B-0.1%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_4%3D2000%284.641%29%5Cimplies%20S_4%3D9282%20)
<h2>189 boys is 54%</h2><h2>x is 46%(100-54)</h2><h2>Cross multiply:</h2><h2>189*46%=54%*x</h2><h2>86.94=0.54x</h2><h2>x=161</h2><h2>189 boys 161 girls</h2><h2>350 altogether</h2><h2>Hope this helps plz hit the crown :D</h2>
The answer is 21g hope this helps :)
