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stiks02 [169]
2 years ago
11

What kind of function describes this situation?

Mathematics
2 answers:
Sauron [17]2 years ago
7 0

Answer:

That'd be linear because it is at a constant rate of deduction

umka21 [38]2 years ago
7 0

Answer: A

Step-by-step explanation:

because she's deducting 10 points every day the slope is constant so it has to be a linear equation

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Step-by-step explanation:

2+2+2-2+4-8= 4-2+4-8=0

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Find all the second partial derivatives. v = e5xey
Helga [31]
I'm taking the liberty of editing your  function  <span>v = e5xey:  It should be 
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<span>v = e^5x^ey, with " ^ " indicating exponentiation.
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Did you mean e^(5x) or (e^5)x?  I'll assume it's e^(5x).

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NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

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We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

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Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

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Then:

c  = 2d = 2*(-1) = -2

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So the values are:

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  • a = -1
  • c = -2
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If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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