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lesya [120]
3 years ago
8

Find the measure of angle BAC

Mathematics
1 answer:
Anon25 [30]3 years ago
7 0
I can not seem to be able to read the picture however a circle must add up to 360 degrees so if you have the other 2 angle measurements then you can figure it out by adding the 2 angles then subtracting that from 360 and there is your answer
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Solve 3x^2=-12x-15 using a quadratic equation with complex solutions
adelina 88 [10]

The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

What is Quadratic equation?

An algebraic equation of the second degree is called a quadratic equation.

Given that;

A quadratic equation is;

3x² = -12x - 15

Now, The equation is written as;

3x² + 12x + 15 = 0

Take 3 common, we get;

3 (x² + 4x + 5) = 0

x² + 4x + 5 = 0

Factorize the equation by using Sridharacharya Formula;

x = - 4 ± √4² - 4*1*5 / 2*1

x = -4 ± √16 - 20 / 2

x = - 4 ± √-4 / 2

Since, √-1 = i

x = -4 ± 2i / 2                            

x = - 2 ± i

It gives two values of x as;

x = - 2 + i

And, x = - 2 - i

Hence, The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

Learn more about the quadratic equation visit:

brainly.com/question/24334139

#SPJ1

5 0
1 year ago
Given f(x) = x3 - x2 + 4x - 1 and<br> g(x) = -2x, find lim g(f(x))<br> X-2
trapecia [35]

Answer:

I hope this helps!Let me know if it helps

6 0
3 years ago
Can someone please help me
nadya68 [22]

Answer:

<u>Right</u><u> </u><u>option</u><u> </u><u>is</u><u> </u><u>B</u><u>.</u><u> </u>

Step-by-step explanation:

\sf  \longrightarrow \frac{ \sec x \sin( - x)  +  \tan( - x) }{1 +  \sec( - x) }  \\  \\  \sf \longrightarrow  \frac{ \sec x( -  \sin x) -  \tan x}{1 +  \sec x}  \\  \\  \sf  \longrightarrow   \frac{  - \frac{1}{ \cos x } \times  \sin x -  \tan x }{1 +  \sec x}  \\  \\  \sf  \longrightarrow \frac{ -  \tan x -  \tan x}{1 +  \sec x}   \\  \\  \sf  \longrightarrow  \frac{ - 2 \tan x}{1 +  \sec x}  \\  \\  \sf \longrightarrow   \frac{  \frac{ - 2 \sin x}{ \cos x} }{1 +  \frac{1}{ \cos x} }  \\  \\  \sf  \longrightarrow  \frac{  \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} }  \\  \\     \boxed{  \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1}  }}

4 0
2 years ago
Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye
slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

37% of freshmen do not visit their counselors regularly.

This means that \pi = 0.37

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}

\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2

n = 1030.4

Rounding up:

A sample size of 1031 is required.

4 0
3 years ago
Can you help me find the side??? It's trigonometry!!
olganol [36]

Answer: 5.6

===================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(B) = AB/BC

cos(62) = AB/12

12*cos(62) = AB

AB = 12*cos(62)

AB = 5.63365875

AB = 5.6

8 0
3 years ago
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