3 years ago

Using exponents, which expression is equivalent to 15^3*15^-6?

Mathematics

1 answer:

abruzzese [7]3 years ago

7 0

A pick A I hope this helps

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Suppose that the cost of producing n pairs of shoes is given by the expression c(n)=30+5n. the average cost of producing a pair

makkiz [27]

<h3>Given</h3>

$c(n)=30+5n\\a(n)=\dfrac{c(n)}{n}$

$\dfrac{d}{dn}(a(n))\quad\text{at n=10}$

<h3>Solution</h3>

$\dfrac{d}{dn}(a(n))=\dfrac{d}{dn}\left(\dfrac{30+5n}{n}\right)=\dfrac{d}{dn}\left(30n^{-1}+5\right)\\\\=-30n^{-2}\\\\=-30\cdot 10^{-2}\qquad\text{at n=10}\\\\=-0.30$

The derivative of the average cost function at n=10 is -0.30.

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3 years ago

Express this number in scientific notation.<br> 78 million

e-lub [12.9K]

7.8 x 10^7

I don’t know how to explain it but it’s right

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3 years ago

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I need help on 5 a and b

coldgirl [10]

A: 63.75
B: 95.625 dollars

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3 years ago

a school debate team has 4 girls and 6 boys. A total of 4 of the team members will be chosen to participate in the district deba

Gemiola [76]

4g and 6b and that's a total of 10 in all so you know it will be 1/2 if its going to be two out of two

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3 years ago

FG ∥ CB, A ∈ FG, D ∈ AB, E ∈ AC

andrey2020 [161]

Answer:

The value of x is $31^{\circ}$ .

Step-by-step explanation:

Please look at the figure attached to get more clear solution.

We have given:

FG||CB

And the line that cut the parallel line is transversal so, here BA is transversal

And alternate interior angles on transverse line are equal

So, ∠1=∠4

And ∠4= $28^{\circ}$

Hence, ∠1=∠4= $28^{\circ}$

And On FG the sum of angles will be $180^{\circ}$

∠3+∠2+∠1= $180^{\circ}$

$90^{\circ}$ +∠2+ $28^{\circ}$ = $180^{\circ}$

Hence, ∠2= $62^{\circ}$

Now, we know that the sum of interior angles is equal to the exterior angle:

Therefore, ∠2+∠5=∠6+∠7

$62^{\circ}+3x=x+4x$

On simplification we get:

$2x=62^{\circ}$

$x=31^{\circ}$

Hence, the value of x is $31^{\circ}$ .

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3 years ago