I really need help, I am on the practice.

Mathematics

1 answer:

morpeh [17]3 years ago

8 0

Sorry I can't help these answers don't make any sense

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The perimeter of a rectangular field is 360yd. The length is 20yd longer than the width. Find the dimensions

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If P=360, then 360yd / 4 sides = 90yds each side. Now that it is a rectangle, the Length should be more than the width, so if the length is 20yds more than the width, do 90 - 20 two times, Width= [ (90yds - 20yds)*2 ]

To sum things up, Length = 110; Width = 70. | 110*2 = 220, 70 * 2 = 140, 220+140 = 360.

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What are the magnitude and direction of u+v+w ?

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The magnitude and the direction of the resultant are approximately 57.871 and 198.676°.

<h3>How to determine the magnitude and the direction of a resultant</h3>

Vectors are elements with two given characteristics: Magnitude and direction. A resultant is derived from the sum of vectors, the magnitude is the norm of a vector and the direction is the orientation of a vector. The resultant and its characteristics are described below:

<h3>Resultant</h3>

$\vec r = \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)$ (1)

<h3>Magnitude</h3>

$\|\vec r\| = \sqrt{\left(\sum\limits_{i=1}^{n} x_{i}\right)^{2}+\left(\sum\limits_{i=1}^{n} y_{i}\right)^{2}}$ (2)

<h3>Direction</h3>

$\theta = \tan^{-1}\frac{\sum\limits_{i=1}^{n}y_{i}}{\sum\limits_{i=1}^{n}x_{i}}$ (3)

Where $\theta$ is resultant angle, measured in degrees.

If we know that $\|\vec u\| = 90$ , $\theta_{u} = 40^{\circ}$ , $\|\vec v\| = 60$ , $\theta_{v} = 20^{\circ}$ , $\|\vec w\| = 40$ and $\theta_{w} = 30^{\circ}$ , then the resultant, its magnitude and its direction:

<h3>Resultant</h3>

$\vec r = (-90\cdot \cos 40^{\circ}-60\cdot \sin 20^{\circ}+40\cdot \cos 30^{\circ}, 40\cdot \sin 30^{\circ}+60\cdot \cos 20^{\circ}-90\cdot \sin 40^{\circ})$